Answer:
Network scan
Explanation:
Cyber security can be defined as preventive practice of protecting computers, software programs, electronic devices, networks, servers and data from potential theft, attack, damage, or unauthorized access by using a body of technology, frameworks, processes and network engineers.
Some examples of cyber attacks are phishing, zero-day exploits, denial of service, man in the middle, cryptojacking, malware, SQL injection, spoofing etc.
Generally, a security assessment is carried out by network security experts on a regular basis to determine potential loopholes or vulnerabilities in the information and technology (IT) infrastructure. One of the techniques or approach used in security assessment is a network scan.
A network scan is a security assessment technique used for the automatic detection of host systems on a network. Although a network scan isn't capable of discovering or detecting all the weaknesses on a network, it avails users information about the computer systems that are active on the network and what services the computer systems offer or what ports are available on them.
Answer:
Explanation:
The program in this code is written correctly and has the messages applied in the code. Therefore, the only thing that would need to be done is pass the correct integers in the code. If you pass the integer 100 contestants for last year and 300 for current year. Then these inputs will provide the following output as requested in the question.
The competition is more than twice as big this year!
This is because the current year would be greater than double last years (100 * 2 = 200)
Answer:
office online
Explanation:
office online is a free online version of Microsoft office suite. it includes Microsoft word, Microsoft excel, Microsoft power point, one note. It allows users to create and edit files online.
#include <iostream>
using namespace std;
int main() {
const int SCORES_SIZE = 4;
int oldScores[SCORES_SIZE];
int newScores[SCORES_SIZE];
int i = 0;
oldScores[0] = 10;
oldScores[1] = 20;
oldScores[2] = 30;
oldScores[3] = 40;
/* Your solution goes here */
for (i = 0; i < SCORES_SIZE; ++i) {
cout << newScores[i] <<" ";
}
cout << endl;
return 0;
}
