Based on the rules of the game, the probability that a person wins the game is 3/8 or 37.5%.
If participants can only win 25% of the time, the number that they need to get would be 32 or higher.
The probability of a winning score of 36 or higher in four consecutive attempts is 1/1,296.
To show that the game is fair, the teacher can post that every number apart from 24 and 30 has an equal chance of appearing.
<h3>What is a good sample space to represent the data?</h3>
There are 6 sides to dice and 4 cards. The sample space is:
Dice Card Product Frequency of Product
1 5 5 1
1 6 6 1
1 7 7 1
1 8 8 1
2 5 10 1
2 6 12 1
2 7 14 1
2 8 16 1
3 5 15 1
3 6 18 1
3 7 21 1
3 8 24 2
4 5 20 1
4 6 24 1
4 7 28 1
4 8 32 1
5 5 25 1
5 6 30 2
5 7 35 1
5 8 40 1
6 5 30
6 6 36 1
6 7 42 1
<u>6 8 48 1</u>
<u>Total 24</u>
24 and 30 have frequencies of 2 as they appear twice.
From the table, in order to win, a player needs to get 28 or higher.
There are only 8 numbers that are 28 or higher but including the chance that 30 has a relative frequency of 2, we have 9 chances to win the game. The probability is:
= 9 / 24
= 3 / 8
<h3>How can a player win 25% of the time?</h3>
If people are to win only 25% of the time, this means that the number of products that can be picked is:
= 25% x 24
= 6
To find the winning number, count down from the highest product 6 times to get 32.
A person therefore needs to get 32 or above to win 25% of the time.
<h3 /><h3>What is the probability of winning the large price?</h3>
The probability of getting 36 or higher is:
= Chance of 36 + chance of 40 + chance of 42 + chance of 48
= 1 / 24 + 1/24 + 1/24 + 1/24
= 1 / 6
The probability of repeating this 4 times is:
= 1 / 6 x 1 / 6 x 1/ 6 x 1 / 6
= 1 / 1,296
Find out more on frequency tables at brainly.com/question/27820465.
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