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3 years ago

Would anyone please help me with these if they can?

Mathematics

1 answer:

lianna [129]3 years ago

5 0

Answer:

12) F.0

13) 3/2

Step-by-step explanation:

12)

(5, 0) and (10, 0)

Slope:

m=(y2-y1)/(x2-x1)

m=(0-0)/(10-5)

m = 0

13)

(3, 2) and (-1, -4)

Slope:

m=(y2-y1)/(x2-x1)

m=(-4-2)/(-1-3)

m=(-6)/(-4)

m= 3/2

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6) Andy is going kyacking. He has $341 to spend on parking and paddles. Parking costs $30 and paddles cost $45. 20 per person. D

telo118 [61]

6 people can go kayaking, use the equation 341=30+45.20x.

7 0

3 years ago

What’s the meaning of pi and how to find the volume of a cylinder. Only do number 1 !!

Triss [41]

Answer:

to find volume of cylinder use formula=

$\pi {rh}^{2}$

and

$\pi = 22 \div 7 \: or \: 3.14$

3 0

3 years ago

Ann took a taxi home from the airport. The taxi fare was $2.10 and she gave the driver a tip of $5. Ann paid a total of $49.10

storchak [24]

Answer:

42 dollars

Step-by-step explanation:

3 0

3 years ago

The oil prices for 2014, rounded to the nearest dollar, were: 95, 101, 101, 102, 102, 106, 104, 97, 93, 84, 76, 59. what is the

kipiarov [429]

Interquartile Range (IQR) = $Q_3-Q_1$ , with $Q_3$ as the upper quartile and $Q_1$ as the lower quartile.

Firstly, rearrange the data so that it's in ascending order: $\{59,76,84,93,95,97,101,101,102,102,104,106\}$

Next, find the median:

$\{59,76,84,93,95,\boxed{97,101,}101,102,102,104,106\}\\\\\frac{97+101}{2}\\\\\frac{198}{2}\\\\99$

Now to find the lower quartile, find the "median" of the data set that's to the left of 99:

$\{\overbrace{59,76,84,93,95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\{\overbrace{59,76,\boxed{84,93}95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\frac{84+93}{2}\\\\\frac{177}{2}\\\\88.5$

Now to find the upper quartile, it's the similar process as finding the lower quartile, except that you are finding the "median" of the data set to the right of 99:

$\{59,76,84,93,95,97,\overbrace{101,101,102,102,104,106}^{\textsf{to the right of the median}}\}\\\\\{59,76,84,93,95,97,\overbrace{101,101,\boxed{102,102} 104,106}^{\textsf{to the right of the median}}\}\\\\\frac{102+102}{2}\\\\\frac{204}{2}\\\\102$

Now that we have the upper and lower quartile, subtract them:

$102-88.5=13.5$

<u>In short, the IQR of this data set is 13.5.</u>

8 0

3 years ago

What is the slope of the following table?

Bess [88]

Answer:

$- \frac{1}{2}$

Step-by-step explanation:

the x rate of change is +2 and the y rate of change if -1. slope is always y over x, therefore, do exactly that. put y (-1) over x (2). thus gett in your answer of the slope.

5 0

3 years ago