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nlexa [21]
2 years ago
15

(correct answers only)

Mathematics
2 answers:
Vlada [557]2 years ago
8 0
  • Initial velocity=11.8m/s=u
  • Acceleration=a=6.39m/s²
  • Distance=s=55m
  • Time be t

According to second equation of kinematics

  • s=ut+1/2at²
  • 55=11.8t+1/2(6.39)t²
  • 110=23.6t+6.39t²
  • 6.39t²+23.6t-110=0

Take positive value

  • t=2.7s
deff fn [24]2 years ago
4 0

Answer:

2.7 s  (1 d.p.)

Step-by-step explanation:

Use the <u>Constant Acceleration Equations</u> where:

  • s = displacement in meters
  • u = initial speed in m/s
  • v = final speed in m/s
  • a = acceleration in m/s²
  • t = time in s (seconds)

Given:

  • s = 55 m
  • u = 11.8 m/s
  • a = 6.39 m/s²

\begin{aligned}\text{Using }s & =ut+\dfrac{1}{2}at^2\\\implies 55 & =11.8t+\dfrac{1}{2}(6.39)t^2\end{aligned}

Rearrange the equation to equal zero:

\implies 3.195t^2+11.8t-55=0

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Use the quadratic equation to solve for t:

\implies a=3.195, \quad b=11.8, \quad c=-55

\implies t=\dfrac{-11.8 \pm \sqrt{11.8^2-4(3.195)(-55)} }{2(3.195)}

\implies t=2.694780675, -6.388051411

As time is <u>positive</u>:

\implies t=2.694780675... \:\text{s}

\implies t=2.7 \: \text{s (1 d.p.)}

Learn more about SUVAT equations here:

brainly.com/question/26241670

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