I think its 1.32 but dont quote me on that
Answer: true if I jump from their then their will no chance to back
We know that
The Standard Form<span> of a </span>Quadratic Equation<span> is
</span> ax²<span> + bx + c = 0
</span>
then
for x=0 y=-6
a*0² + b*0 + c = -6---------> c=-6
for x=1 y=2
a*1² + b*1 -6 = 2---------> a+b=8---------> a=8-b---------> equation 1
for x=3 y=-0
a*3² + b*3 -6 = 0---------> 9a+3b=6---------> equation 2
<span>substituting 1 in 2
9*(8-b)+3b=6------> 72-9b+3b=6---------> 6b=66--------> b=11
a=8-11-------> a=-3
so
a=-3
b=11
c=-6
</span>Standard Form of a Quadratic Equation is
-3x² + 11x - 6 = 0
<span>
the answer is
</span> -3x² + 11x - 6 = 0<span>
</span>
<span>Equation:
0.15x + 0.10(5-x) = 0.11*5
---
Multiply thru by 100:
15x + 10*5 - 10x = 11*5
---
5x = 5
x = 1 liter (amt. 15% oj needed)
----
5-x = 4 liters (amt of 10% oj needed)
======</span>
Answer:
19 = x
Step-by-step explanation:
The square of the tangent segment = The product of (whole secant segment) (the outside part of the secant segment)
BD²= (BA)(BE)
8² = (4 + x - 7) (4) BA = BE + EB
8² = (x - 3)(4)
64 = 4x - 12
64 + 12 = 4x
76 = 4x
19 = x
