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Phoenix [80]
2 years ago
6

Solve the following proportion by cross multiplying: x / 8 = 28 / 32

Mathematics
2 answers:
AveGali [126]2 years ago
6 0
Since it is an equality that means the left side of the equation (x/8) has to be equal to the right side of the equation (28/32). One way you can solve for x is to isolate it. Since it’s an equality like we said you have to do to the left side the same that you would do to the right side to isolate x. So if I multiply by 8 on the left I need to also multiply by 8 on the right. So 8* (x/8) becomes just x since 8x/8 becomes 8/8 * x which is 1 *x. On the right side we do 8 *(28/32) which becomes 28 * 8/32 which becomes 7. So x = 7.
vova2212 [387]2 years ago
4 0

Answer:  x = 7

Step-by-step explanation:

\frac{x}{8} =\frac{28}{32}

We cross multiply, and we get:

32x = 8(28)

32x = 224

    x = 7

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What is the equation for an arithmetic sequence with a first term of 8 and a second term of 5? an = 8 − 5(n − 1) an = 8 + 5(n −
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an =a1+d(n-1)

where d is the common difference

d=5-8

d=-3

a1=8

an =8-3(n-1)

Choice C

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3 years ago
There are 10 balls in a bag numbered from 1 to 10. Three balls are selected at random without replacement.
VikaD [51]

Answer:

A=1000

B=3.33

Step-by-step explanation:

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2 years ago
X+17.4=23.5 ??????????
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5 0
3 years ago
Find an equivalent ratio in simplest terms:<br> 15 : 72
maksim [4K]

Answer:

5:24

Step-by-step explanation:

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7 0
2 years ago
Al abrir su alcancía Beatriz encontró que entre monedas de 5, 10 y 25 centavos completaba $ 9.50. Encontró igualmente que el núm
vladimir2022 [97]

Answer:

67 monedas de 5, 34 de 10 y 11 de 25.

Step-by-step explanation:

Representemos el primer enunciado de manera algebraica:

5x+10y+25z =950  (1)

Donde:

  • x es el numero de monedas de 5
  • y es el numero de monedas de 10
  • z es el numero de monedas de 25

Ahora, el número de monedas de 10 centavos era el triple de las de 25 centavos y que las de 5 centavos era el doble de las de 10 centavos, se puede representar como:

y=3z  (2)              

x=2y  (3)    

     

Combinado las eacuaciones (1), (2) y (3) tenemos:

5(2y)+10y+25(\frac{y}{3}) =950

10y+10y+\frac{25}{3}y =950

\frac{85}{3}y =950  

y =34

Por lo tanto el valor de x y z seran:

x=2(34)          

x=68          

z=11    

Si ponemos cada valor en la equacion (1), tenemos:

5(68)+10(34)+25(11) =955

Como el resultado da 955 hay un excedente de 5 pesos, asi que finalmente tendremos.

x = 67

y = 34

z = 11  

Espero te haya serrvido!

4 0
3 years ago
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