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aniked [119]
3 years ago
12

Given that a function, h, has a domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25 and that h(8) = 19 and h(-2) = 2, select the

statement that could be true for h.
A.

h(13) = 18

B.

h(-3) = -1

C.

h(8) = 21

D.

h(2) = 16

Mathematics
1 answer:
miskamm [114]3 years ago
5 0

Answer:

Actually two points belong to the Domain and Range of this function, namely C, (8,21) D (2,16) and could be true for h(x)

Step-by-step explanation:

1) In other words,  we have two pairs (8,19) and (-2,2):

2) Plugging in each values on every condition:

D=-3 \leqslant x \leqslant 11 \:\:\:R= 1 \leqslant h(x) \leqslant 25\\A)D=-3 \leqslant 13 \leqslant 11 \:\:\:R= 1 \leqslant 18 \leqslant 25\:\:\:\:FALSE\\B)D=-3 \leqslant -3 \leqslant 11 \:\:\:R= 1 \leqslant -1 \leqslant 25 \:FALSE\\C)D=-3 \leqslant 8 \leqslant 11 \:\:\:R= 1 \leqslant 21 \leqslant 25\:True\\D)D=-3 \leqslant 2 \leqslant 11 \:\:\:R= 1 \leqslant 16 \leqslant 25\: True

We have two points that belong to the Domain and Range.

3) Actually two points belong to the Domain and Range of this function, namely C, (8,21) D (2,16) and could be true for h(x)

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DedPeter [7]

Answer:

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=39 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1 represent the population standard deviation

n=25 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

And replacing we got:

ME= 1.96 *\frac{1}{\sqrt{25}}= 0.392

Now we have everything in order to replace into formula (1):

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

7 0
3 years ago
...im failing please
Taya2010 [7]

Answer:

top row on 9 page; 9) 53/5 10) 26/4 11) 37/4

bottom row on 9 page; 9) 8 and 1/7 10) 6 and 3/4 11) 1 and 1/3

top row on 3 page; 3) 2 and 2/7 4) 5 and 3/4 5) 8 and 1/10

bottom row on 3 page; 3) 4/3 4) 3/2 5) 12/5

top row on 12 page; 12) 21/10 13) 62/6 14) 57/6

bottom row on 12 page; 12) 1 and 9/10 13) 10 and 1/2 14) 3 and 3/8

Step-by-step explanation:

You never specified if these had to be simplified or turned into a fraction, so I just simplified them. That's about it.

I hope this helps :)

7 0
2 years ago
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