The area of the base of cube B is 25/9 times larger than the area of the base of cube A.
<h3>How many times larger is the base area of cube B than the base area of cube A? </h3>
Because the cubes are similar, then we know that the dimensions of cube B are a dilation of scale factor K of the dimensions of cube A.
Then, the volume of cube B is K³ times the volume of cube A.
The area of any face of cube B is K² times the area of any face of cube A
From this we can write:
125 in³ = K³*27in³
(125/27) = K³
If we apply the cubic root in both sides, we get:
∛(125/27) = K = 5/3
Then the relation between the areas is equal to:
K² = (5/3)^2 = 25/9
The area of the base of cube B is 25/9 times larger than the area of the base of cube A.
If you want to learn more about dilations:
brainly.com/question/3457976
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