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2 years ago

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Cube A and cube B are similar solids. The volume of cube A is 27 cubic inches, and the volume of cube B is 125 cubic inches. How

many times larger is the base area of cube B than the base area of cube A? A small cube labeled cube A has points K, L, M, and N on the top face and O, P, Q, and R on the bottom face. A large cube labeled cube B has points A, B, C, and D on the top face and E, F, G, and H on the bottom face. A. B. C. D.

1 answer:

katovenus [111]2 years ago

5 0

The area of the base of cube B is 25/9 times larger than the area of the base of cube A.

<h3>How many times larger is the base area of cube B than the base area of cube A? </h3>

Because the cubes are similar, then we know that the dimensions of cube B are a dilation of scale factor K of the dimensions of cube A.

Then, the volume of cube B is K³ times the volume of cube A.

The area of any face of cube B is K² times the area of any face of cube A

From this we can write:

125 in³ = K³*27in³

(125/27) = K³

If we apply the cubic root in both sides, we get:

∛(125/27) = K = 5/3

Then the relation between the areas is equal to:

K² = (5/3)^2 = 25/9

The area of the base of cube B is 25/9 times larger than the area of the base of cube A.

If you want to learn more about dilations:

brainly.com/question/3457976

#SPJ1

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