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BabaBlast [244]
2 years ago
10

a. In the general education course requirement at a college, a student needs to choose one each from social sciences, humanities

, natural sciences, and foreign languages. There are 5 social science courses, 4 humanity courses, 4 natural science courses, and 3 foreign language courses available for general education. How many different ways can a student choose general education courses from these 4 areas?
Mathematics
1 answer:
Elenna [48]2 years ago
5 0

Using the Fundamental Counting Theorem, there are 240 ways to choose general education courses from these 4 areas.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

Considering the number of options for each course, the parameters are given as follows:

n_1 = 5, n_2 = 4, n_3 = 4, n_4 = 3.

Hence the number of ways is given by:

N = 5 x 4 x 4 x 3 = 240.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

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Answer:

<em>y = (-4/3)*x + 7</em>

<em />

Step-by-step explanation:

The point-slope form of the equation of a line is: <em>y = a*x + b </em>

In the above equation, <em>a </em>is the slope of the line representing the equation in the graph and y is the function of x [y = y(x)]

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=> The equation of this line has a form as following: <em>y = (-4/3)*x + b (1)</em>

<em />

As the line passes through the point (9; -5) (in which: x = 9; y = -5). Replace x =9 and y = -5 into the equation (1), we have:

<em>y = (-4/3)*x + b</em>

<em>=> -5 = (-4/3)*9 + b </em>

<em>=> -5 = -12 + b </em>

<em>=> b = 7</em>

<em />

So that the equation in point-slope form of the given line is:

<em>y = (-4/3)*x + 7</em>

<em />

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