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4 years ago

For what values of (m) does the graph of y=mx²-5x-2 have no x-intercepts?

1 answer:

5 0

You need to find where the discriminant is less than zero
Remember the discriminant is b^2 - 4ac
a = m
b = -5
c = -2
Set up the inequality like this
(-5)^2 - 4m(-2) < 0
25 + 8m < 0
8m < -25
m < -25/8 < -3.125

So any number less than -3.125 will make this graph have no x-intercepts (or real roots)

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3 years ago

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The LARGEST angle has a measure of ______degrees

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3 years ago

A bag contains green marbles and blue marbles,

dexar [7]

There are 13 green marbles in the bag.

Step-by-step explanation:

Total marbles = 18

Let,

Green marbles = x

Blue marbles = y

According to given statement;

The number of green marbles is 2 less than 3 times the number of blue marbles.

x = 3y-2 Eqn 1

x+y=18 Eqn 2

Putting value of x from Eqn 1 in Eqn 2;

$(3y-2)+y=18\\3y-2+y=18\\4y=18+2\\4y=20$

Dividing both sides by 4

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Keywords: linear equation, substitution method

Learn more about linear equations at:

#LearnwithBrainly

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4 years ago

Please help me answer this question

Drupady [299]

Answer:

64 ft^3

Step-by-step explanation:

Assuming that all of the values (length [l], width [w] and height [h]) are all 4ft then using the calculation l x w x h, we can see that the answer is 64ft^3.

I hope this helps!

[Hey if this is wrong, don't post a rude reply! Message me and I will try to correct the answer!]

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3 years ago

A quadrilateral has vertices A, B, C, and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units

Kryger [21]

Answer:

The correct option is O B'

Step-by-step explanation:

We have a quadrilateral with vertices A, B, C and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units away from the line, C is 7 units away from the line and D is 9 units away from the line.

Now we perform the reflection and we obtain a new quadrilateral A'B'C'D'.

In order to apply the reflection to the original quadrilateral ABCD, we perform the reflection to all of its points, particularly to its vertices.

Wherever we have a point X and a line of reflection L and we perform the reflection, the new point X' will keep its original distance from the line of reflection (this is an important concept in order to understand the exercise).

I will attach a drawing with an example.

Finally, we only have to look at the vertices and its original distances to answer the question.

The vertice that is closest to the line of reflection is B (the distance is 4 units). We answer O B'

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3 years ago