The two parabolas intersect for

and so the base of each solid is the set

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas,
. But since -2 ≤ x ≤ 2, this reduces to
.
a. Square cross sections will contribute a volume of

where ∆x is the thickness of the section. Then the volume would be

where we take advantage of symmetry in the first line.
b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

We end up with the same integral as before except for the leading constant:

Using the result of part (a), the volume is

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

and using the result of part (a) again, the volume is

Answer:
Use the slope formula and slope-intercept form y
=
m
x
+
b to find the equation. y
=
−
x
+
4
To find the product of <span>-2x^3+x-5 and x^3-3x-4, we need to multiply each term in the first polynomial by the second polynomial. (So, x^3 - 3x - 4) times ....
-2x^3 = -2x^6 + 6x^4 + 8x^3
x = x^4 - 3x^2 - 4x
-5 = -5x^3 + 15x + 20
If we add all these together, we get (-2x^6 + 7x^4 + 3x^3 - 3x^2 + 11x + 20)</span>
Answer:
i.e answer A.
Step-by-step explanation:
This question involves knowing the following power/exponent rule:
![\sqrt[n]{x^m} = x^\frac{m}{n} \\\\so \sqrt[7]{x^2} = x^\frac{2}{7} \\\\and \\\\ \sqrt[5]{y^3} = y^\frac{3}{5} \\](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%3D%20x%5E%5Cfrac%7Bm%7D%7Bn%7D%20%5C%5C%5C%5Cso%20%5Csqrt%5B7%5D%7Bx%5E2%7D%20%3D%20x%5E%5Cfrac%7B2%7D%7B7%7D%20%5C%5C%5C%5Cand%20%20%5C%5C%5C%5C%20%5Csqrt%5B5%5D%7By%5E3%7D%20%3D%20y%5E%5Cfrac%7B3%7D%7B5%7D%20%5C%5C)
Next, when a power is on the bottom of a fraction, if we want to move it to the top, this makes the power become negative.
so the y-term, when moved to the top of the fraction, becomes:

So the answer is: 