A^2b^2 + 3ab + 3ab + 3^2
= a^2b^2 + 6ab + 9
perimeter of regular octagon is given as
= 8a
where a is side of regular octagon
so
perimeter = 8 x 20 = 160
so option c is answer
Answer:
x = 6 y = 5
Step-by-step explanation:
-8x + 3y = -33
y = -5x +35
-8x + 3(-5x + 35) = -33
-8x - 15x + 105 = -33
-23x + 105 = -33
-23x = -138
x = 6
-8(6) + 3y = -33
-48 + 3y = -33
3y = 15
y = 5