Point-slope equation for perpendicular lines y=-2x-7 that passes through (-2,-3)
1 answer:
Answer: below! ^^
Step-by-step explanation:
Hii, do you need an answer to your question? Let me help you out! (;
<h2>. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .</h2><h2>Part 1 ⚜</h2>Perpendicular lines have slopes that are opposite inverses of each other.
The slope (m) of the line that is perpendicular to y=-2x-7 is .
Voila! There's our answer, cheers! (:
<h2>. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .</h2><em>Hope I helped! Best wishes!</em>
<em>Reach far. Aim high. Dream big.</em>
<em />
You might be interested in
Answer:
The slope of the new road is 0.
Step-by-step explanation:
- the slope of d street line is tan(90)
[if the angle made by a line with x axis is then, the slope of that line will be tan(
) ]
- here, the angle made by the d street line with x axis is 90 degrees.
- if a road is to be built which is perpendicular to d street , it should make 0 degrees i.e, it should be parallel to x axis .
- so, the slope of new road will be tan(0) = 0