The line of symmetry of the parabola whose equation is y = ax^2 -4x + 3 is
1 answer:
Answer:
B. -1
Step-by-step explanation:
If we have a parabola whose equation is:
The line of symmetry is calculated as:
Now, we have the equation and the line of symmetry is
Where:
So, we can replace by -4 and
by -2 and solve for
using the following equation as:
It means that the equation of the parabola is equal to:
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The vertex-form equation is
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 = {-5, 3}
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 = {-5, 3}