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Valentin [98]
1 year ago
5

Find K such that the number 23K10 is divisible by 2, 3, and 5 2021

Mathematics
1 answer:
blsea [12.9K]1 year ago
5 0

The values of K that will make 23K10 to be divisible by 2, 3 and 5 are; 0, 3, 6 and 9

<h3>How to use divisibility rules?</h3>

We want to find the number K in 23K10 that will make it divisible by 2, 3 and 5.

Now, for the number to be divisible by 2, 3 and 5, then it means it must be divisible by the LCM which is; 2 * 3 * 5 = 30

Now, the divisibility rule for 30 is that it must be divisible by 3 and 10.

If 23K10 is divisible by 3, sum of digits will be multiple of 3.

Thus;

2 + 3 + K + 1 + 0 = K + 6 must be equal to 0, 3, 6, 9, 12, 15, 18....

Thus, K could either be 0, 3, 6 or 9

Read more about Divisibility Rules at; brainly.com/question/9462805

#SPJ1

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<span>There are 4 long rows and 5 short rows in the theater. x represents the number of chairs in each long row and y represents the number of chairs in each short row.

So, total number of chairs in 4 long rows= 4x
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Total number of chairs in the theater on a normal day = 4x + 5y

When 2 chairs are added to each long row, the number of chairs will change to (x+2).
So, total number of chairs in 4 long rows will be = 4(x+2)

When 3 chairs are added to each short row, the number of chairs will change to (y+3)
So, total number of chairs in 5 short rows will be = 5(y+3)

Thus, total number of chairs in the theater in rush day = 4(x+2) + 5(y+3)
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Thus we can say the number of chairs increase by 23 as compared to a normal day.
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7 0
3 years ago
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What is the answer to 2x to the power of 2 +x +1=0
KonstantinChe [14]

Answer:

x=-1

Step-by-step explanation:

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13 less than 8 times a number is the same as the number plus 1
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Given sinθ=- 3/5 and cscθ=-5/3 in quadrant III, find the value of other trigonometric functions using a Pythagorean Identity. Sh
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Let ABC be a triangle in the 3rd quadrant, right-angled at B. 
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 Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
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