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Y_Kistochka [10]
3 years ago
13

:Phil’s age decreased by 9 years is 14 years ?

Mathematics
1 answer:
Crank3 years ago
8 0

Answer:

Phil is 23

Step-by-step explanation:

Add 14 to 9 and you get 23. So then you subtract 9 from 23

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Help me plz! if you can
IgorLugansk [536]
Answer: 180/540
Simplified term would be 1/3
The answer is b
3 0
3 years ago
Find the measure of the largest angle.
mihalych1998 [28]

Answer:

4x-7

Step-by-step explanation:

Solve for x:

180 = 44 + 3x - 11 + 4x - 7

Combine like terms: 180 = 26 + 7x

Simplify: 154 = 7x

Simplify: 22 = x

Substitute: 3(22) - 11 = 55 and 4(22) - 7 = 81

Create inequality: 44 < 55 < 81

8 0
3 years ago
Read 2 more answers
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
4 years ago
An equation is shown below:
lbvjy [14]

Step-by-step explanation:

Step 1: 12x-6= 1

step 2:12x=7

5 0
3 years ago
Enter the ordered pair for point J.
AfilCa [17]
I think it is (1,1.5)
8 0
3 years ago
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