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timurjin [86]
2 years ago
10

Let v = leftanglebracket 3, negative 2 rightanglebracket. what is the approximate direction angle of v?

Mathematics
1 answer:
givi [52]2 years ago
7 0

The approximate direction angle of v is 326°

Definition of Direction Angle

A vector's direction angle is the angle formed by the positive x-axis and the vector v. The arctangent of the ratio between the vertical and horizontal components of the vector, v=xi+yj, can be used to determine the direction angle, θ.

What is the direction angle of v?

Let θ be the direction angle of v or the angle mad by v with the horizontal line.

It is given that,

v = < 3, -2 >

We know that,

θ = tan⁻¹(\frac{y}{x})

Here, we have y = -2 and x = 3. Hence, we get,

∴ θ = tan⁻¹(\frac{-2}{3})

⇒θ = tan⁻¹(0.66)

Hence the direction angle of v = 360 - tan⁻¹(0.66)

≈ 326°

Thus, the approximate direction angle of v is 326°.

Learn more about direction angle here:

brainly.com/question/12977024

#SPJ4

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A 12-cm-long thin rod has the nonuniform charge density λ(x)=(2.0 nC/cm)e−|x|/(6.0 cm), where x is measured from the center of t
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Answer:

the total charge is

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Step-by-step explanation:

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separating the integral from -6 to 0 and from 0 to 6, taking into account that |x|=-x for x<0 and |x|=x for x >=0, we getQ=\int^{0}_{-6}2\exp\left(\frac{x}{6}\right)dx+\int^{6}_{0}2\exp\left(\frac{-x}{6}\right)dx

using the substitution x=-u in the first integral we get\int^{0}_{-6}2\exp\left(\frac{x}{6}\right)dx=-\int^{0}_{6}2\exp\left(\frac{-u}{6}\right)du=\int^{6}_{0}2\exp\left(\frac{-u}{6}\right)du

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Answer: is bruh idk

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