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blsea [12.9K]
3 years ago
12

Please Help Me! ASAP!

Mathematics
1 answer:
Radda [10]3 years ago
6 0

Answer:

two solutions

Step-by-step explanation: it cant be no solution because no solution will be a vertical line it can be one solution becuase y=x is a solution and so is y=4

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Solve 4X^2+7 = 8X +4 by using the quadratic formula
Sergio [31]

Answer:

(1.5,0)

(.5,0)

Step-by-step explanation:

Quadratic formula below

We first need to move everything to one side of the equation

4x²-8x+3=0

Then plug everything in

(8±√(-8²-4*4*3))/(2*4)

(8±√16)/8

To calculate the ± we need to do when where it's adding and then negative

we have

(8+4)/8=3/2

and hten

(8-4)/8=1/2

4 0
3 years ago
-14 farenheit in the morning, dropped by 7 farenheit.
umka21 [38]
The answer is negative 21
7 0
3 years ago
Read 2 more answers
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
(09.06 HC) The function H(t) = −16t2 + 112t + 24 shows the height H(t), in feet, of a cannon ball after t seconds. A second cann
erma4kov [3.2K]
PART A:

The table of h(t) and g(t) for the value of x between 4 and 7 inclusive are shown below.

The solution for h(x)=g(x) lies between x = 4 and x = 5, this is becuase the range of value given by h(4) and h(5) and g(4) and g(5). 

The graph is shown in picture 2 to confirm this. The two functions intersect each other between x = 4 and x = 5

PART B: 

The point of intersection is the point where the cannon balls will collide. 
3 0
3 years ago
Read 2 more answers
Which equation can be used to solve for x in the diagram ?
kotegsom [21]
D because a straight line is 180 degrees. Since 2x+15 and 65 add up to a straight line (180 degrees) in the picture, the answer is D.
6 0
3 years ago
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