Answer:
(1.5,0)
(.5,0)
Step-by-step explanation:
Quadratic formula below
We first need to move everything to one side of the equation
4x²-8x+3=0
Then plug everything in
(8±√(-8²-4*4*3))/(2*4)
(8±√16)/8
To calculate the ± we need to do when where it's adding and then negative
we have
(8+4)/8=3/2
and hten
(8-4)/8=1/2
The answer is negative 21
Answer:
The number of trees at the begging of the 4-year period was 2560.
Step-by-step explanation:
Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was
, and for the next three years we have that
Start End
Second year
-------------- 
Third year
-------------
Fourth year
--------------
So the formula to calculate the number of trees in the fourth year is
we know that all of the trees thrived and there were 6250 at the end of 4 year period, then
⇒
Therefore the number of trees at the begging of the 4-year period was 2560.
PART A:
The table of h(t) and g(t) for the value of x between 4 and 7 inclusive are shown below.
The solution for h(x)=g(x) lies between x = 4 and x = 5, this is becuase the range of value given by h(4) and h(5) and g(4) and g(5).
The graph is shown in picture 2 to confirm this. The two functions intersect each other between x = 4 and x = 5
PART B:
The point of intersection is the point where the cannon balls will collide.
D because a straight line is 180 degrees. Since 2x+15 and 65 add up to a straight line (180 degrees) in the picture, the answer is D.