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2 years ago

What is the value of the rational expression below when is equal to 5?

Mathematics

1 answer:

yaroslaw [1]2 years ago

7 0

Answer:

$\boxed {C. -2}$

Step-by-step explanation:

$\textsf {Substitute x = 5 in the expression :}$

$\longrightarrow \mathsf{\frac{15 - x}{x - 10}}$

$\longrightarrow \mathsf{\frac{15 - 5}{5 - 10}}$

$\longrightarrow \mathsf{\frac{10}{-5}}$

$\longrightarrow \mathsf{-2}$

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PLZ help! Find the surface area and volume. Leave your answers in terms of TT.

Butoxors [25]

<h2><u>Solution</u>:-</h2>

1. Radius (r) of the sphere = 10 units. (Given)

• Surface area of the sphere = 4πr².

Surface area of the sphere = 4 × π × (10)²

Surface area of the sphere = 4 × π × 10 × 10

Surface area of the sphere = 400π units. (Ans)

And,

• Volume of the sphere = 4/3πr³.

Volume of the sphere = 4/3 × π × (10)³

Volume of the sphere = 4/3 × π × 10 × 10 × 10

Volume of the sphere = 4000π/3

Volume of the sphere = 1333.3π cubic units. [approx] (Ans)

__________________________________

2. Diameter of the sphere = 16 units. (Given)

Radius (r) of the sphere = 16/2 = 8 units.

• Surface area of the sphere = 4πr².

Surface area of the sphere = 4 × π × (8)²

Surface area of the sphere = 4 × π × 8 × 8

Surface area of the sphere = 256π units. (Ans)

And,

• Volume of the sphere = 4/3πr³.

Volume of the sphere = 4/3 × π × (8)³

Volume of the sphere = 4/3 × π × 8 × 8 × 8

Volume of the sphere = 2048π/3

Volume of the sphere = 682.6π cubic units. [approx] (Ans)

__________________________________

3. Radius (r) of the sphere = 5 units. (Given)

• Surface area of the sphere = 4πr².

Surface area of the sphere = 4 × π × (5)²

Surface area of the sphere = 4 × π × 5 × 5

Surface area of the sphere = 100π units. (Ans)

And,

• Volume of the sphere = 4/3πr³.

Volume of the sphere = 4/3 × π × (5)³

Volume of the sphere = 4/3 × π × 5 × 5 × 5

Volume of the sphere = 500π/3

Volume of the sphere = 166.6π cubic units. [approx] (Ans)

__________________________________

4. Diameter of the sphere = 18 units. (Given)

Radius (r) of the sphere = 18/2 = 9 units.

• Surface area of the sphere = 4πr².

Surface area of the sphere = 4 × π × (9)²

Surface area of the sphere = 4 × π × 9 × 9

Surface area of the sphere = 324π units. (Ans)

And,

• Volume of the sphere = 4/3πr³.

Volume of the sphere = 4/3 × π × (9)³

Volume of the sphere = 4/3 × π × 9 × 9 × 9

Volume of the sphere = 2916π/3

Volume of the sphere = 972π cubic units. (Ans)

__________________________________

5 0

3 years ago

X intercept f(x)=(x+4)^2

natali 33 [55]

Answer:

Step-by-step explanation:

Given the function f(x)=(x+4)², <u>the x intercept occurs at f(x) = 0,</u> substituting f(x) = 0 into the given equation to get the value of x we have;

$0 = (x+4)^{2} \\$

Taking the square root of both sides

$\sqrt{(x+4})^{2} = \sqrt{0}\\ x+4 = 0\\$

Subtracting 4 from both sides of the equation

$x+4-4 = 0-4\\x = -4$

Therefore the x intercept of the equation is -4

4 0

3 years ago

If a scale distance of 3.5 inches on a map represent an actual distance of 175 km what actual distance does a scale distance of

gavmur [86]

Considering the definition of map and scale, an actual distance of 269.59 km represent a scale distance of 5.7 inches .

<h3>Definition of map and scale</h3>

A map is a representation of a place, at a size smaller than the real size.

The scale of a cartographic representation is the relationship of similarity between the real dimensions of the geographical space represented and those of its image on the map. That is, the scale is defined as the proportionality relationship that exists between a distance measured on the ground and its corresponding measurement on the map.

One way to represent the scale is by a fraction, which indicates the proportion between the distance on a map and its corresponding distance in reality:

$Scale=\frac{distance on the map}{distance in reality}$

<h3>Actual distance in this case</h3>

In this case, you know that a scale distance of 3.5 inches on a map represent an actual distance of 175 km.

To know the real distance that represents a scale distance of 5.7 inches, as the scale ratio is the same as in the previous case, it is expressed:

$\frac{3.7 inches}{175 km}=\frac{5.7 inches}{distance in reality}$