Answer:
I think its
y=32
x=5
If I'm wrong, I am so sorry! I am just getting started, and I just wanted to help you
Step-by-step explanation:
You pretty much just flip the second fraction and factor
Answer:35
Simplifying
5(x + 20) = 7x + 30
Reorder the terms:
5(20 + x) = 7x + 30
(20 * 5 + x * 5) = 7x + 30
(100 + 5x) = 7x + 30
Reorder the terms:
100 + 5x = 30 + 7x
Solving
100 + 5x = 30 + 7x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-7x' to each side of the equation.
100 + 5x + -7x = 30 + 7x + -7x
Combine like terms: 5x + -7x = -2x
100 + -2x = 30 + 7x + -7x
Combine like terms: 7x + -7x = 0
100 + -2x = 30 + 0
100 + -2x = 30
Add '-100' to each side of the equation.
100 + -100 + -2x = 30 + -100
Combine like terms: 100 + -100 = 0
0 + -2x = 30 + -100
-2x = 30 + -100
Combine like terms: 30 + -100 = -70
-2x = -70
Divide each side by '-2'.
x = 35
Simplifying
x = 35
Hope it helps. Please tell me if im correct
<em>Answer:</em>
Complete proof is written below.
Facts and explanation about the segments shown in question :
- As BC = EF is a given statement in the question
- AB + BC = AC because the definition of betweenness gives us a clear idea that if a point B is between points A and C, then the length of AB and the length of BC is equal to the length of AC. Also according to Segment addition postulate, AB + BC = AC. For example, if AB = 5 and BC= 7 then AC = AB + BC → AC = 12
- AC > BC because the Parts Theorem (Segments) mentions that if B is a point on AC between A and C, then AC > BC and AC>AB. So, if we observe the question figure, we can realize that point B lies on the segment AC between points A and C.
- AC > EF because BC is equal to EF and if AC>BC, then it must be true that the length of AC must greater than the length segment EF.
Below is the complete proof of the observation given in the question:
<em />
<em>STATEMENT REASON </em>
___________________________________________________
1. BC = EF 1. Given
2. AB + BC = AC 2. Betweenness
3. AC > BC 3. Def. of segment inequality
4. AC > EF 4. Def. of congruent segments
<em />
<em>Keywords: statement, length, reason, proof</em>
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Answer:
P ≈ 48.89°(nearest hundredth)
Step-by-step explanation:
The triangle PQR forms a right angle triangle since angle R is 90°. The triangle has an hypotenuse , adjacent and opposite side.
Using the SOHCAHTOA principle one can find the sine ratio of angle P. Let us designate where each side represent.
opposite side(QR) = 55
adjacent side(PR) = 48
hypotenuse(PQ) = 73
sin P = opposite/hypotenuse
sin P = 55/73
P = sin⁻¹ 55/73
P = sin⁻¹ 0.75342465753
P = 48.8879095605
P ≈ 48.89°(nearest hundredth)