5/(x-5)=x/(x-5)-5/4.
Multiply through by 4(x-5):
20=4x-5(x-5).
20=4x-5x+25=25-x, x=5.
This is an extraneous solution because when x=5, the denominators become zero so division by zero occurs, and the result is meaningless.
In this question, we want to compare several numbers with different denominators and find out which number is the least. To compare this number, we have to change the denominator into the same number by finding the least common multiple (LCM) of the 4 numbers. The factor of each number will be:
3= 3 ^1
5= 5^1
8= 2 * 2 * 2 = 2^3
2= 2^1
We can find the LCM by multiplying a higher exponent of each prime number. The LCM will be:3^1 * 5^1 * 2^3 = 120
Each number will be:
Tiger= 2/3 * 40/40= 80/120
Redbird = 4/5 * 24/24= 96/120
Bulldogs = 3/8 * 15/15 = 45/120
Titans = 1/2 * 60/60 = 60/120
As you can see, the team with the lowest chance to play is Bulldogs = 45/120
When you divide by a fraction, flip the fraction over and change divide to multiply:
3/2 / 1/8 would become:
3/2 x 8/1
8/1 simplifies to 8
You get:
3/2 x 8 = 12
The answer is:
Three-halves times 8 = 12
Step-by-step explanation:
there is no diagram so I'm just going to guess this however
sin x = 6/9
sin x = 2/3
sin x = 0.67
x = sin inverse of 0.67
x = 42.1
