Question

20 points!!

Answer 1

See below for the proof of the equation $\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)$

How to prove the equation?

The equation is given as:

$\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)$

Take the LCM

$\frac{(ax + by)(x - y) -(ax - by)(x + y)}{(x + y)(x - y)}= 2(a - b)$

Expand

$\frac{ax^2 - axy + bxy - by^2 -ax^2 - axy + bxy + by^2}{(x + y)(x - y)}= 2(a - b)$

Evaluate the like terms

$\frac{-2axy + 2bxy }{(x + y)(x - y)}= 2(a - b)$

Rewrite as:

$\frac{-2axy + 2bxy }{x^2 - y^2}= 2(a - b)$

Factorize the numerator

$\frac{2(a - b)(x^2 - y^2)}{x^2 - y^2}= 2(a - b)$

Divide

2(a - b)= 2(a - b)

Both sides are equal

Hence, the equation $\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)$ has been proved

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