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ohaa [14]
2 years ago
11

What is the value of the following radical expression?

Mathematics
2 answers:
svlad2 [7]2 years ago
7 0

\large\displaystyle\text{$\begin{gathered}\sf Apply \ the \ laws \ of \ exponents:\sqrt[n]{-a}=-\sqrt[n]{a}, if \ n \ is \ odd \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \sqrt[5]{-32}=-\sqrt[5]{32}   \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{=-\left(-\sqrt[5]{32}\right)} \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Decompose \ the \ number \ into \  prime \ factors: 32=2^{5}. \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{=-\left(-\sqrt[5]{2^5}\right)} \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Apply \ the \ laws \ of \ exponents:\sqrt[n]{a^n}=a,\:\quad \:a\ge 0 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \sqrt[5]{2^5}=2 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Remove \ parentheses:\quad \:-\left(-2\right)=2 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{=2 \ \ \to \ \ \ Answer} \end{gathered}$}

<h2>{ Pisces04 }</h2>
coldgirl [10]2 years ago
6 0

Answer:

b.) 2

Explanation:

Given:

  • \sf  - \sqrt[\sf 5]{\sf -32}

rewrite knowing 2⁵ = 32, (-2)⁵  = -32

  • \sf -\left(\sqrt[5]{(-2)^5}\right)

simplify, ⁿ√xⁿ = x

  • \sf -\left(-2}\right)

distribute inside parenthesis

  • \sf 2
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