If the wall with 4 ft. of storage area can fit 6 sections of plant and the wall with 7 ft. Can fit 5, that means each section is 3 ft. because 7-4=3, so that extra section on the wall with 4 ft. You do this because there is one extra section on the wall with four. Knowing this, the wall with 7 ft. Would be the 7 ft. + 5 sections of 3 ft. So 7+(5x3) = 22. On the wall with 4 ft., do the same,
4+(6x3) =22. Since they are equal and the walls are supposed to be equal, we can confirm this is the right answer
Answer:
B. 12.5 feet below the surface of the water
Step-by-step explanation:
-20 + (-32.5) + 40
40 - 52.5
= -12.5 feet
= 12.5 feet below the water
The most important part of this question is understanding the words of the problem. The trick lies in the words of the problem. Once the web of words is simplified, the problem becomes very easy. The main thing is converting the words into numbers.
Let us assume the unknown number = x
Then from the question we get
(x/4) = (x/5) + 1
(x/4) - (x/5) = 1
(5x - 4x)/20 = 1
x/20 = 1
x = 20
So the unknown number is 20
A=number of seats in section A
B=number of seats in section B
C=number of seats in section C
We can suggest this system of equations:
A+B+C=55,000
A=B+C ⇒A-B-C=0
28A+16B+12C=1,158,000
We solve this system of equations by Gauss Method.
1 1 1 55,000
1 -1 -1 0
28 16 12 1,158,000
1 1 1 55,000
0 -2 -2 -55,000 (R₂-R₁)
0 12 16 382,000 (28R₁-R₂)
1 1 1 55,000
0 -2 -2 -55,000
0 0 4 52,000 (6R₂+R₃)
Therefore:
4C=52,000
C=52,000/4
C=13,000
-2B-2(13,000)=-55,000
-2B-26,000=-55,000
-2B=-55,000+26,000
-2B=-29,000
B=-29,000 / -2
B=14,500.
A + 14,500+13,000=55,000
A+27,500=55,000
A=55,000-27,500
A=27,500.
Answer: there are 27,500 seats in section A, 14,500 seats in section B and 13,000 seats in section C.
