(1-cos^2x/cosx)*cosecx
(sin^2x/cosx)*sinx (where 1-cos^2x=sin^2x) and 1/cscx=sinx
sinx/cosx=tanx(divide by sinx)
hence proved
We are given
x1 = 10 ft
y1 = 14 ft
x2 = 13 ft
y2 = 9 ft
We are asked to find the distance between the base of the house to the closest treetop.
So,
d1 = √(10² + 14²) = 17.20
d2 √(13² + 9²) = 15.81
The distance is 15.81 ft to the closest treetop which is the tree 13 feet from the base of the house.
Y = -(1/2)x + 4
y + (1/2)x =4
(1/2)x + y = 4
Multiply both sides by 2
2*(1/2)x + 2*y = 2*4
x + 2y = 8
Option B.
50*25= 1250
2mins 15seconds= 135 seconds
135*3= 405
1250-405 = 845
Your score is 845
Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
