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bonufazy [111]
2 years ago
7

Mia has 24 yards of ribbon. She gave 10 yards to her sister. Mia now wants to work on a project that requires 2 1/4 yards of rib

bon per project. What is the greatest number of projects Mia can complete with this ribbon.
(Optional, just please write down step by step explanation) PLEASE ANSWER WITH EXPLANATION AS IF YOU WERE WRITING DOEN ON SCRATCH PAPER
Mathematics
1 answer:
Anon25 [30]2 years ago
4 0

Answer:

6 projects

Step-by-step explanation:

Original ribbon length = 24 yards

After 10 yards given to sister, Mia is left with 24-10 = 14 yards of ribbon

Each project requires 2 1/4 yards of ribbon.

2 1/4 is 9/4 yards as an improper fraction (2 * 4 + 1 is the numerator and the denominator is unchanged)

We now have to figure out how many times 9/4 yards goes into 14 yards.

For this,

14 ÷ 9/4.
To do this, flip the numerator and denominator of the fraction and multiply

14 ÷ 9/4 = 14 × 4/9 = 56/9 . We ignore any remainder.

9 goes into 56 6 times with remainder of 2 (ignore remainder)
In other words the greatest number of projects = 6

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Ratio: 6: 16 Value of the Ratio:  3/8

Ratio: 12: 32 Value of the Ratio: 3/8

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Step-by-step explanation:

Equivalent ratios:

To get if ratios are equivalent we look for the constant between ratios

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We apply the method of comparing the first term of both ratios ,  and the second term of both ratios.  We see the constant is 5 ( 1/5 is equal to 2/10)

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<u>So,  we can that the first ratio is equivalent to the second,  then, third ratio is equivalent to the forth.  </u>

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Ratio: 1: 2 Value of the Ratio:  1/2

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<u>If the values are equivalent the ratios are equivalent.</u>

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