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Len [333]
2 years ago
14

Problem 4

Mathematics
1 answer:
Sonbull [250]2 years ago
7 0

Answer:

286+390+468÷3= answer

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if an airplane consumes 30.25 gallons of fuel in 2.8 hours of flying how many gallons will it consume and 4.3 hours of flying?​
wariber [46]

Answer:

46.46 gallons

Step-by-step explanation:

we know that

An airplane consumes 30.25 gallons of fuel in 2.8 hours of flying

so

using proportion

Find out how many gallons will it consume in 4.3 hours of flying

\frac{30.25}{2.8}\ \frac{gal}{h}=\frac{x}{4.3}\ \frac{gal}{h}\\\\x=30.25*(4.3)/2.8\\\\x= 46.46\ gal

5 0
3 years ago
6. Find the area of a triangle with sides a = 5, b = 8, and c = 11.​
Colt1911 [192]
<h2>20</h2>

Hi, I’m Lena and I’ll be here to answer your question with a good-quality answer. If there's something I can improve, let me know! ツ

♡ Let’s look at the main important things that will lead you in the correct path.

♥ <em>a </em>+<em> b</em> usually = <em>c!</em> Unless the book asks you to find a specific variable, you will most likely be looking for <em>c</em>.

♥ <em>A</em> = <em>bh</em>/2! This is the formula for the area of a triangle. You can also read this as A = base * height/2. The good thing about this formula is you don't need a picture. You can write it as <em>a</em> * b<em> </em>or <em>b</em> * <em>a!</em>

<em />

♡ Now, let's solve!

♥ Plug the numbers into the formula: 5*8/2.

♥ Solve! In this case, we do not need c: 40/2 = 20.

Your answer should be 20! Please do not hesitate to ask me any questions.

3 0
3 years ago
The difference between four-fifths of a number and 23 is greater than 1
oee [108]

(4/5)n -23>1

+23 +23

(4/5) n > 24

*5/4 *5/4

n > 30

3 0
3 years ago
How to solve the question
zavuch27 [327]
2/7 ×5/8
so 2×5 =10
and 7 ×8 = 56
your answer is 10/56
3 0
3 years ago
Read 2 more answers
The mean salary of actuaries is LaTeX: \mu=\$100,000????=$100,000 and the standard deviation is LaTeX: \sigma=\$36,730????=$36,7
krek1111 [17]

Answer:

The lower limit of 95% confidence interval is 99002.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $100,000

Sample mean, \bar{x} = $111,000

Sample size, n = 36

Alpha, α = 0.05

Population standard deviation, σ = $36,730

First, we design the null and the alternate hypothesis

H_{0}: \mu = \$100,000\\H_A: \mu \neq \$100,000

We have to find the lower limit of the 95% confidence interval.

95% Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

111000 \pm 1.96(\dfrac{36730}{\sqrt{36}} )\\\\ = 111000 \pm 11998.4667 \\= (99001.5333,122998.4667)\\ \approx (99002,122999)

The lower limit of 95% confidence interval is 99002.

6 0
4 years ago
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