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VARVARA [1.3K]
2 years ago
8

Select the correct answer. Consider the following system of equations. Use this graph of the system to approximate its solution.

A diagonal curve rises through (negative 5, 1) through (6, 6). A diagonal curve declines through (negative 6, 5) through (7, negative 6) on the x y coordinate plane. A. B. C. D.

Mathematics
1 answer:
vesna_86 [32]2 years ago
7 0

The approximate solution to the given system of equations, considering the graph, is given as follows:

D. \left(-\frac{13}{4}, \frac{5}{2}\right).

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

On a graph, the solution of a system of equations is given by the intersection between the curves. In this graph, the intersection of the two curves happen close to x = -3.25, y = 2.5, hence the solution is approximated by:

D. \left(-\frac{13}{4}, \frac{5}{2}\right)

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

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A
navik [9.2K]

Answer:

The number of liters of 50% antifreeze solution is 50 and the number of liters of 90% antifreeze solution is 150

Step-by-step explanation:

Let

x ----> number of liters of 50% antifreeze solution

y ----> number of liters of 90% antifreeze solution

we know that

50%=50/100=0.50

90%=90/100=0.90

80%=80/100=0.80

x+y=200

x=200-y ------> equation A

0.50x+0.90y=0.8(200) -----> equation B

substitute equation A in equation B and solve for y

0.50(200-y)+0.90y=160

100-0.50y+0.90y=160

0.40y=160-100

0.40y=60

y=150 liters

Find the value of x

x=200-y

x=200-150=50 liters

therefore

The number of liters of 50% antifreeze solution is 50

The number of liters of 90% antifreeze solution is 150

3 0
3 years ago
Read 2 more answers
The value of a school bus reduces from $512000 to $343000in 3 years. Find the
Eva8 [605]

Answer:

<em>The uniform rate of depreciation is $56,333 per year, or 11% per year.</em>

Step-by-step explanation:

<u>Rate of Depreciation</u>

If some object has a certain value P and after some time t its value decreases to Q, the rate of depreciation is a measure of how much its value changed per unit time.

It can be calculated as:

\displaystyle R=\frac{P-Q}{t}

It can also be expressed as a percentage, dividing the previous value by P.

The school bus reduces its value from $512,000 to $343,000 in 3 years, thus:

\displaystyle R=\frac{512,000-343,000}{3}

\displaystyle R=\frac{169,000}{3}

R = 56,333 $/year

Expressed as a percentage:

R = 56,333 / 512,000 = 0.11

R = 11%/year

The uniform rate of depreciation is $56,333 per year, or 11% per year.

8 0
3 years ago
One triangle on a graph has a vertical side of 7 and a horizontal side of 12.
Alisiya [41]
If you are working out the diagonal line you need to use Pythagoras Theroum: c² = a²+b²

c² = 7²+12² = 193
√c² = c = √193 = 13.89

The length of the diagonal side is 13.89,
Hope this helps! :)
4 0
3 years ago
What 2 numbers add up to get 17 and multiply to get -308??
Rufina [12.5K]
A) x + y = 17
B) x * y = -308

B) y = -308 / x Substituting this into A)
A) x -308 / x = 17
A) x^2 -308 = 17x
A) x^2 -17x -308 = 0
x = 28
y = -11


5 0
3 years ago
A ski patrol unit has nine members available for duty, and two of them are to be sent to rescue an injured skier. In how many wa
alexgriva [62]

Answer:

36

Step-by-step explanation:

The number of two of the nine members of ski patrol unit can be chosen is equal to the combinations of 9 taken 2. This can be calculated using the formula:

\frac{9!}{2!*(9-2)!}  

= \frac{9!}{2!*7!}, where

9! =9×8×7×6×5×4×3×2×1 and

7!=7×6×5×4×3×2×1

2!=2×1   then the equation becomes:

=\frac{9*8}{2} =36

4 0
2 years ago
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