Answer:
The number of liters of 50% antifreeze solution is 50 and the number of liters of 90% antifreeze solution is 150
Step-by-step explanation:
Let
x ----> number of liters of 50% antifreeze solution
y ----> number of liters of 90% antifreeze solution
we know that
50%=50/100=0.50
90%=90/100=0.90
80%=80/100=0.80
x+y=200
x=200-y ------> equation A
0.50x+0.90y=0.8(200) -----> equation B
substitute equation A in equation B and solve for y
0.50(200-y)+0.90y=160
100-0.50y+0.90y=160
0.40y=160-100
0.40y=60
y=150 liters
Find the value of x
x=200-y
x=200-150=50 liters
therefore
The number of liters of 50% antifreeze solution is 50
The number of liters of 90% antifreeze solution is 150
Answer:
<em>The uniform rate of depreciation is $56,333 per year, or 11% per year.</em>
Step-by-step explanation:
<u>Rate of Depreciation</u>
If some object has a certain value P and after some time t its value decreases to Q, the rate of depreciation is a measure of how much its value changed per unit time.
It can be calculated as:

It can also be expressed as a percentage, dividing the previous value by P.
The school bus reduces its value from $512,000 to $343,000 in 3 years, thus:


R = 56,333 $/year
Expressed as a percentage:
R = 56,333 / 512,000 = 0.11
R = 11%/year
The uniform rate of depreciation is $56,333 per year, or 11% per year.
If you are working out the diagonal line you need to use Pythagoras Theroum: c² = a²+b²
c² = 7²+12² = 193
√c² = c = √193 = 13.89
The length of the diagonal side is 13.89,
Hope this helps! :)
A) x + y = 17
B) x * y = -308
B) y = -308 / x Substituting this into A)
A) x -308 / x = 17
A) x^2 -308 = 17x
A) x^2 -17x -308 = 0
x = 28
y = -11
Answer:
36
Step-by-step explanation:
The number of two of the nine members of ski patrol unit can be chosen is equal to the combinations of 9 taken 2. This can be calculated using the formula:
=
, where
9! =9×8×7×6×5×4×3×2×1 and
7!=7×6×5×4×3×2×1
2!=2×1 then the equation becomes:
=
=36