Question

What is the perimeter of A ABC?

Answer 1

Answer: 11.4

Step-by-step explanation:

Using the distance formula,

$AC=\sqrt{(-3-1)^2 + (-1-2)^2}}=5\\\\AB=\sqrt{(-3-0)^2 +(-1-3)^2}=5\\\\BC=\sqrt{(1-0)^2 + (2-3)^2}=\sqrt{2} \approx 1.4\\\\\implies P \approx 5+5+1.4=\boxed{11.4}$