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8_murik_8 [283]
2 years ago
9

Which statement is true?

Mathematics
1 answer:
zhuklara [117]2 years ago
4 0

Answer:

C) When an altitude is drawn from the right angle of a right triangle it creates three similar triangles.

Step-by-step explanation:

The Inscribed Similar Triangles Theorem states that if an altitude is drawn from the right angle of any right triangle, then the two triangles formed are similar to the original triangle and all three triangles are similar to each other.

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A pyramid has a square base of length 8cm and a total surface area of 144cm². Find the volume of the pyramid. (Please use Pythag
Sveta_85 [38]

Answer:

\displaystyle V_{ \text{pyramid}}= 64 \:  {cm}^{3}

Step-by-step explanation:

we are given surface area and the length of the square base

we want to figure out the Volume

to do so

we need to figure out slant length first

recall the formula of surface area

\displaystyle A_{\text{surface}}=B+\dfrac{1}{2}\times P \times s

where B stands for Base area

and P for Base Parimeter

so

\sf\displaystyle \: 144=(8 \times 8)+\dfrac{1}{2}\times (8 \times 4) \times s

now we need our algebraic skills to figure out s

simplify parentheses:

\sf\displaystyle \: 64+\dfrac{1}{2}\times32\times s = 144

reduce fraction:

\sf\displaystyle \: 64+\dfrac{1}{ \cancel{ \: 2}}\times \cancel{32}  \: ^{16} \times s = 144 \\ 64 + 16 \times s = 144

simplify multiplication:

\displaystyle \: 16s + 64 = 144

cancel 64 from both sides;

\displaystyle \: 16s = 80

divide both sides by 16:

\displaystyle \: \therefore \: s = 5

now we'll use Pythagoras theorem to figure out height

according to the theorem

\displaystyle \:  {h}^{2}  +  (\frac{l}{2} {)}^{2}  =  {s}^{2}

substitute the value of l and s:

\displaystyle \:  {h}^{2}  +  (\frac{8}{2} {)}^{2}  =  {5}^{2}

simplify parentheses:

\displaystyle \:  {h}^{2}  +  (4 {)}^{2}  =  {5}^{2}

simplify squares:

\displaystyle \:  {h}^{2}  +  16  =  25

cancel 16 from both sides:

\displaystyle \:  {h}^{2}   =  9

square root both sides:

\displaystyle \:   \therefore \: {h}^{}   =  3

recall the formula of a square pyramid

\displaystyle V_{pyramid}=\dfrac{1}{3}\times A\times h

where A stands for Base area (l²)

substitute the value of h and l:

\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times  \{8 \times 8 \}\times 3

simplify multiplication:

\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times  64\times 3

reduce fraction:

\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{ \cancel{ 3 \: }}\times  64\times \cancel{ \:  3}

hence,

\sf\displaystyle V_{ \text{pyramid}}= 64 \:  {cm}^{3}

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Answer:

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Step-by-step explanation:

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Solve the equation<br> cb – 20 = –10 for b.
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You have to isolate the variable by dividing each side by factors that don’t contain the variable
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