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8_murik_8 [283]
1 year ago
9

Which statement is true?

Mathematics
1 answer:
zhuklara [117]1 year ago
4 0

Answer:

C) When an altitude is drawn from the right angle of a right triangle it creates three similar triangles.

Step-by-step explanation:

The Inscribed Similar Triangles Theorem states that if an altitude is drawn from the right angle of any right triangle, then the two triangles formed are similar to the original triangle and all three triangles are similar to each other.

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Flag question
xz_007 [3.2K]

Answer:

b. cosx + 6 sinx

Step-by-step explanation:

\frac{d}{dx} ( sinx - 6 cos \: x) \\  \\  = \frac{d}{dx}  sinx  - 6\frac{d}{dx}   cos \: x \\  \\  = cos \: x - 6( - sin \: x) \\  \\  = cos \: x + 6 \: sin \: x

7 0
2 years ago
Read 2 more answers
A triangle has a side lengths of 34in., 28in., and 42in. is the triangle an acute, right, or obtuse?
jenyasd209 [6]
It would be an acute
3 0
2 years ago
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Please help me with this question
inna [77]
What data is the table referring to?
7 0
3 years ago
Which expression is equivalent to n2 + 26n + 88 for all values of n?
Lelechka [254]

Answer:

Option B is correct.

The expression which is equivalent to  n^2+26n+88  is; (n+22)(n+4)

Explanation:

Given the equation: n^2+26n+88 for all values of n.

The quadratic equation in this form; ax^2+bx+c =0

First find two numbers that multiply to give ac and add to give b.

From the given equation;

a =1 , b = 26 and c =88

then,

the two number that multiply to give ac =88 is, 22 or 4

and they add up to give b=26 (i.e 22+4)

Now, rewrite the middle term i.e 26n with 22n and 4n , we have

n^2+22n+4n+88=0

Now, factor the first two terms and last two terms,

n(n+22)+4(n+22)

we see that (n+22) is common to both terms so, we have;

(n+22)(n+4)

Therefore, the expression (n+22)(n+4) is equivalent to  n^2+26n+88

Check:

(n+4)(n+22) = n\cdot n+ 22n+4n+88=n^2+26n+88   [ True]



5 0
3 years ago
Read 2 more answers
In ΔGHI, the measure of ∠I=90°, the measure of ∠G=62°, and GH = 96 feet. Find the length of IG to the nearest tenth of a foot.
alexandr402 [8]

Answer:

45.1feet

Step-by-step explanation:

Given the following

∠I=90°

∠G=62°, and

GH = 96 feet = Hypotenuse

Required

IG = Adjacent side

Using the SOH CAH TOA identity

Cos theta = Adj/hyp

Cos 62 =IG/96

IG = 96cos62

IG = 96(0.4695)

IG = 45.1feet

Hence the length of IG to the nearest tenth is 45.1feet

6 0
2 years ago
Read 2 more answers
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