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dexar [7]
2 years ago
10

A cylindral drill with radius 5 cm is used to bore a hole through the center of a sphere with radius 9 cm. Find the volume of th

e ring-shaped solid that remains.
Mathematics
1 answer:
masya89 [10]2 years ago
3 0

The volume of the ring-shaped remaining solid is <u>1797 cm³</u>.

The volume is the total space occupied by an object.

The volume of a sphere of radius r units is given as (4/3)πr³.

The volume of a cylinder with radius r units and height h units is given as πr²h.

In the question, we are asked to find the volume of the remaining solid when a sphere of radius 9cm is drilled by a cylindrical driller of radius 5cm.

The volume will be equal to the difference in the volumes of the sphere and cylinder, where the height of the cylinder will be taken as the diameter of the sphere (two times radius = 2*9 = 18) as it is drilled through the center.

Therefore, the volume of the ring-shaped remaining solid is given as,

= (4/3)π(9)³ - π(5)²(18) cm³,

= π{972 - 400} cm³,

= 572π cm³,

= 1796.99 cm³ ≈ 1797 cm³.

Therefore, the volume of the ring-shaped remaining solid is <u>1797 cm³</u>.

Learn more about volumes of solids at

brainly.com/question/14565712

#SPJ4

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Cube A has a side length of 3 meters and cube B has a side length of 6 meters. Calculate the volume of the two cubes. Which stat
Pavel [41]
A = 3 cubed = 27 cubic meters 

B = 6 cubed = 216 cubic meters.


Cube B is 8 times larger than cube A. 
4 0
3 years ago
Please help!! asap!!! ( 10 points)
MAXImum [283]

Answer:

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Step-by-step explanation:

5 0
4 years ago
A round cake has a diameter of 30 cm. Angela places the cake on a circular cake board with a diameter 5 cm longer than that of t
Stels [109]

Answer:

C = 35 pi

Step-by-step explanation:

The new diameter is 5 + 30 = 35

The circumference = pi * d

The circumference = 35*pi

5 0
3 years ago
The quotient of a number and 5 is less than 4
cupoosta [38]

Answer:

n ÷ 5 < 4

Step-by-step explanation:

Quotient is to divide.

Let n be the unknown number.

Now you have the equation needed.

8 0
3 years ago
A coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that
mafiozo [28]

Answer:

(a) The significance level of the test is 0.002.

(b) The power of the test is 0.3487.

Step-by-step explanation:

We are given that a coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that the probability is not 0.5.

The test rejects the null hypothesis if either 0 or 10 heads are observed.

Let p = <u><em>probability of obtaining head.</em></u>

So, Null Hypothesis, H_0 : p = 0.5

Alternate Hypothesis, H_A : p \neq 0.5

(a) The significance level of the test which is represented by \alpha is the probability of Type I error.

Type I error states the probability of rejecting the null hypothesis given the fact that the null hypothesis is true.

Here, the probability of rejecting the null hypothesis means we obtain the probability of observing either 0 or 10 heads, that is;

            P(Type I error) = \alpha

         P(X = 0/H_0 is true) + P(X = 10/H_0 is true) = \alpha

Also, the event of obtaining heads when a coin is thrown 10 times can be considered as a binomial experiment.

So, X ~ Binom(n = 10, p = 0.5)

P(X = 0/H_0 is true) + P(X = 10/H_0 is true) = \alpha

\binom{10}{0}\times 0.5^{0} \times (1-0.5)^{10-0}  +\binom{10}{10}\times 0.5^{10} \times (1-0.5)^{10-10}  = \alpha

(1\times 1\times 0.5^{10})  +(1 \times 0.5^{10} \times 0.5^{0}) = \alpha

\alpha = 0.0019

So, the significance level of the test is 0.002.

(b) It is stated that the probability of heads is 0.1, and we have to find the power of the test.

Here the Type II error is used which states the probability of accepting the null hypothesis given the fact that the null hypothesis is false.

Also, the power of the test is represented by (1 - \beta).

So, here, X ~ Binom(n = 10, p = 0.1)

1-\beta = P(X = 0/H_0 is true) + P(X = 10/H_0 is true)

1-\beta = \binom{10}{0}\times 0.1^{0} \times (1-0.1)^{10-0}  +\binom{10}{10}\times 0.1^{10} \times (1-0.1)^{10-10}  

1-\beta = (1\times 1\times 0.9^{10})  +(1 \times 0.1^{10} \times 0.9^{0})

1-\beta = 0.3487

Hence, the power of the test is 0.3487.

3 0
3 years ago
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