Answer:
w=5h-8
Step-by-step explanation:
Take the original formula h=(1/5)w+(8/5)
Subtract -8/5 on both sides to isolate the w, so h-8/5=(1/5)w
Now you have to get rid of the 1/5, so multiply 5(h-8/5), the 5 in the 8/5 cross each other out. You are left with 5h-8
Step-by-step explanation:
To tell if JKON and JKLM are similar, compare the ratios between corresponding sides. For example:
JK / KO = 5/8
JK / KL = 5/22
The ratios aren't the same, so the shapes aren't similar.
Answer:
Outlier!! I know it sounds like a cat poster but it's true
Step-by-step explanation:
Answer:
Q13. y = sin(2x – π/2); y = - 2cos2x
Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1
Step-by-step explanation:
Question 13
(A) Sine function
y = a sin[b(x - h)] + k
y = a sin(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Phase shift = π/2.
2h =π/2
h = π/4
The equation is
y = sin[2(x – π/4)} or
y = sin(2x – π/2)
B. Cosine function
y = a cos[b(x - h)] + k
y = a cos(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Reflected across x-axis, y ⟶ -y
The equation is y = - 2cos2x
Question 14
(A) Sine function
(1) Amp = 2; a = 2
(2) Shifted down 1; k = -1
(3) Per = π; b = 2
(4) Phase shift = 0; h = 0
The equation is y = 2sin2x -1
(B) Cosine function
a = 2, b = -1; b = 2
Phase shift = π/2; h = π/4
The equation is
y = -2cos[2(x – π/4)] – 1 or
y = -2cos(2x – π/2) - 1