Question

The following two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally:

Answer 1

The missing statement are:

4.  ∠B ≅ ∠B; Reflexive Property of Equality.

5.   ΔBDE ~ ΔBAC; Side-Angle-Side (SAS) Similarity Postulate.

What are the proofs?

The missing statement are number 4 and 5.

If we say that  4. ∠B ≅ ∠B; Reflexive Property of Equality then:

∠B ≅ ∠B,

Note that  there are two triangles, which are ΔABC and ΔDBE and we also have ∠BDE ≅∠BAC and ∠B ≅ ∠B,

∠BDE + ∠B + ∠BED = 180°

∠BAC + ∠B +  ∠BCA = 180°

Hence, ∠BED = ∠BCA Substitution property of equality

That  birth ΔABC ~ ΔDBE,which is Angle Angle Similarity Postulate

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