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mihalych1998 [28]
3 years ago
10

Help please! ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
solmaris [256]3 years ago
3 0

Answer:

x= 1/2

and y=3

Step-by-step explanation:

Let's solve your system by substitution.

y=10x−2;2x+y=4

Step: Solvey=10x−2for y:

y=10x−2

Step: Substitute10x−2foryin2x+y=4:

2x+y=4

2x+10x−2=4

12x−2=4(Simplify both sides of the equation)

12x−2+2=4+2(Add 2 to both sides)

12x=6

12x

12

=

6

12

(Divide both sides by 12)

x=

1

2

Step: Substitute

1

2

forxiny=10x−2:

y=10x−2

y=10(

1

2

)−2

y=3(Simplify both sides of the equation)

Answer:

x= 1 /2

and y

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James spent $(2y2 + 6). He bought notebooks that each cost $(y2 − 1).
CaHeK987 [17]
The expression to find the number of notebooks James bought would be written as:

Number of notebooks = total spent / cost per item

Number of notebooks = (2y^2 + 6) / <span>(y^2 − 1)

</span><span>If y = 3, then the number of notebooks bought would be:

</span>Number of notebooks = (2y^2 + 6) / (y^2 − 1)
Number of notebooks = (2(3)^2 + 6) / (3^2 − 1)
Number of notebooks = 3 pieces<span>
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7 0
3 years ago
In 2012 your car was worth $10,000. In 2014 your car was worth $8,800. Suppose the value of your car decreased at a constant rat
Sonbull [250]

Answer:

g(t) = 10000(0.938)^t

Step-by-step explanation:

Given data:

car worth is $10,000 in 2012

car worth is $8000 in 2014

let linear function is given as

P(t) = at + b

which denote the value of car in year t

take t =0 for year 2012

at t =0, 10,000 = 0 + b

we get b = 10,000

take t =2 for year 2014

at t =2, P(2) = 2a + b

8800 = 2a + 10,000

a = - 600

Thus the price of car at year t after 2012 is given as p(t) = -600t + 10000

let the exponential function p(t)  =ab^2 where t denote t = 0 at 2012

putting t = 0 P(0) = 10,000 we get 10,000 = ab^0

a = 10,000

putting t = 2 p = 8800

8800 =ab^2

b^2 = \frac{8800}{10000}

b = 0.938

g(t) = 10000(0.938)^t

3 0
3 years ago
I need help with these two problems. [9 and 10] FORMULAS GIVEN!!
zaharov [31]
<h2>Question 9:</h2>

1. Use Pythagorean Theorem (a²+b²=c²) to solve for missing side of triangle and rectangle. x²+16²=20², or x²+256=400. So, x²=144, and x=12

2. Use formula: 1/2(h)(b1+b2). 1/2 (12) (30+14).

3. Simplify: 1/2 (12) (44)=1/2(528)=264

Area of whole figure is 264 square mm.

<h2>Question 10:</h2>

Literally same thing but with trigonometry.

1. Use sine to find out length of dotted line: sin(60°)=x/12

2: Simplify: 12*sin(60°)=x. x≈10.4 (rounded to the nearest tenth)

3. Use Pythagorean Theorem to find out last leg of triangle: 10.4²+x²=12²

4: Simplify: 108.16 +x²=144. x²=35.84 ≈ 6

5: Use formula: 1/2(h)(b1+b2). 1/2 (10.4) (30+36)

6: Simplify: 1/2 (10.4) (66) =343.2

7: Area of figure is about 343.2

Remember, this is an approximate answer with rounding, so it might not be what your teacher wants. The best thing to do is do it yourself again.

4 0
3 years ago
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Veseljchak [2.6K]
C. 8 23/24
One way you can solve this is by dividing 14 1/3 by 8, because it is the denominator of 5/8, then multiplying the quotient by 5, because it is the numerator of 5/8.
6 0
3 years ago
Read 2 more answers
Please help please thanks
alexandr402 [8]
Fraction: 16/75
Decimal: 0.21
8 0
3 years ago
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