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Rainbow [258]
2 years ago
13

What is the slope for (3, 8) and (2, 6). ?

Mathematics
2 answers:
LUCKY_DIMON [66]2 years ago
6 0

Answer:

m = 2

Step-by-step explanation:

m = \frac{rise}{run} =\frac{y_{2}-y_1}{x_2-x_1}

=\frac{6 - 8}{2 - 3} \\= \frac{-2}{-1}\\ = 2

Ivahew [28]2 years ago
4 0

\huge\text{Hey there!}

\huge\textbf{The formula for finding the slope:}

\mathbf{\dfrac{y_2 - y_1}{x_2 - x_1} = slope}

\huge\textbf{Some people understand formula like:}

\mathbf{\dfrac{rise}{run} = slope}

\huge\textbf{Breaking down the question:}

\mathbf{y_2 \rightarrow \boxed{\textbf{6}}}

\mathbf{y_1 \rightarrow \boxed{\textbf{8}}}

\mathbf{x_2 \rightarrow \boxed{\textbf{2}}}

\mathbf{x_1 \rightarrow \boxed{\textbf{3}}}

\huge\textbf{What your equation should look like:}

\mathbf{\dfrac{6 - 8}{2 - 3} = slope}

\huge\textbf{Simplify the equation we came up with:}

\mathbf{\dfrac{6 - 8}{2 - 3} = slope}

\mathbf{\rightarrow \dfrac{-2}{-1} = slope}

\mathbf{\rightarrow -2 \div -1 = slope}

\mathbf{\rightarrow 2 = slope}

\huge\textbf{Thus, the answer should most likely be:}

\huge\boxed{\mathsf{Slope \rightarrow \boxed{\textsf{2}}}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

<h3>~\frak{Amphite1040:)}</h3>
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F(x)2x²+1and g(x)=x²-7find (f+g)(x)
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Answer:

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Step-by-step explanation:

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8 0
4 years ago
Express 140 as a product of its prime factors
gogolik [260]

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4 0
3 years ago
Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the
alexandr1967 [171]

a. 15 students are members of both clubs

b. 50 students only are members of the mathematics club

c. 25 students only are members of the physics club

Step-by-step explanation:

The given is:

  • There are 100 students
  • 65 are members of a mathematics club
  • 40 are members of a physics club
  • 10 are members of neither club

We need to find how many students are members of

a. both clubs?

b. only mathematics club

c. only physics club

∵ The total number of students = 100

∵ 10 are members of neither club

- Subtract 10 from 100 to find the members of the mathematics

  club or the physics club

∵ 100 - 10 = 90

∴ There are 90 members of the mathematics club or physics club

∴ n(mathematics or physics) = 90

∵ 65 students are members of a mathematics club

∵ n(mathematics) = 65

∵ 40 students are members of a physics club

∴ n(physics) = 40

∵ n(mathematics or physics) = n(mathematics) + n(physics) - n(both)

∴ 90 = 65 + 40 - n(both)

∴ 90 = 105 - n(both)

- Add n(both) to each side

∴ n(both) + 90 = 105

- Subtract 90 from each side

∴ n(both) = 15

∴ 15 students are members of both clubs

a. 15 students are members of both clubs

∵ 65 students are members of the mathematics club

∵ 15 of them are members of the physics club

∴ n(mathematics only) = 65 - 15 = 50

∴ 50 students only are members of the mathematics club

b. 50 students only are members of the mathematics club

∵ 40 students are members of the physics club

∵ 15 of them are members of the mathematics club

∴ n(physics only) = 40 - 15 = 25

∴ 25 students only are members of the physics club

c. 25 students only are members of the physics club

Learn more:

You can learn more about word problems in brainly.com/question/8907574

#LearnwithBrainly

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