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Stels [109]
4 years ago
14

Which polynomial expression represents a sum of cubes? (6 – s)(s2 + 6s + 36) (6 + s)(s2 – 6s – 36) (6 + s)(s2 – 6s + 36) (6 + s)

(s2 + 6s + 36)
Mathematics
2 answers:
Triss [41]4 years ago
8 0
C) (6+s) (s2-6s+36) 
For sum of cubes you add the first binomial and subtract then add in the following trinomial.
a3+b3=(a+b)(a2-ab+b2)
Nadusha1986 [10]4 years ago
4 0

Answer:

Option 3 is correct that is (6+s)(s^2-6s+36)

Step-by-step explanation:

 We have general formula for sum of cube which is

a^3+b^3=(a+b)(a^2+b^2-ab)

Here, we have a=s and b=6

on substituting the values in the formula we will get

6^3+s^3=(6+s)(s^2+6^2-6s)

After simplification we will get

6^3+s^3=(6+s)(s^2+36-6s)

After rearranging the terms we will get

6^3+s^3=(6+s)(s^2-6s+36) which exactly matches option 3 in the given options.

Therefore, option 3 is correct that is (6+s)(s^2-6s+36)



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3 years ago
A student solves the following equation and determines that the solution is −2. Is the student correct? Explain. 3 a + 2 − 6a a2
Ganezh [65]

For this case, we have the following equation (according to the comments):

\frac{3}{a+2} - \frac{6a}{a^2-4}  = \frac{1}{a-2}

First, we factor the quadratic expression in the denominator:

\frac{3}{a+2} - \frac{6a}{(a-2)(a+2)}  = \frac{1}{a-2}

Then, we multiply both sides of the equation by (a-2) (a + 2):

\frac{3(a-2)(a+2)}{a+2} - \frac{6a(a-2)(a+2)}{(a-2)(a+2)}  = \frac{(a-2)(a+2)}{a-2}

Later, canceling similar terms we have:

3(a-2) - 6a = a+2

We do distributive property on the left side of the equation:

3a-6-6a=a+2

By grouping variables and constant terms we have:

3a - 6a -a = 2+6

Rewriting we have:

-4a=8

Finally, by clearing "a" we have:

a=-\frac{8}{4} a=-2

Note: the value of a is a extraneous solution because it makes the denominator of the original equation equal to zero.

Answer:

the student correct, but the value of a= -2 is an extraneous solution

8 0
4 years ago
Read 2 more answers
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