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belka [17]
2 years ago
14

A patient admitted to the hospital was prescribed a pain medication to be given every 4 hr and an antibiotic to be given every 5

hr. Bandages applied to the patient's external injuries needed changing every 12 hr. The nurse changed the bandages and gave the patient both medications at 6:00 A.M. Monday morning. A patient admitted to the hospital was prescribed a pain medication to be given every 4 hr and an antibiotic to be given every 5 hr . Bandages applied to the patient's external injuries needed changing every 12 hr . The nurse changed the bandages and gave the patient both medications at 6:00 A.M. Monday morning.​
Mathematics
1 answer:
goldenfox [79]2 years ago
3 0

Answer:

First Question: 1. 60 hours 2. Wednesday 6:00 PM

Step-by-step explanation:

Sorry but I couldn't figure out the answer to the second question :(

Hope this helped :D

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A salesperson earns $300 per week, plus a 25% commission on each sale made. How much would the salesperson earn if he sold $650
Montano1993 [528]

Answer:

$800 = $300 +.05(x), x being the amount that must be sold

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Step-by-step explanation:

5 0
3 years ago
What is the next term of the following sequence? 20, 10, 5, 2 1/2, ... 1 1/2 1 1/4 3/4
Lynna [10]
20\2=10
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4 0
3 years ago
The South Coast Air Basin (Los Angeles, Orange, and San Bernardino counties) does not meet the air quality standards for carbon
Archy [21]

Answer:

0.2225 gr/mile

Step-by-step explanation:

Let's work out first the amount of CO sent out in 1990.

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Now, we must estimate the population for 2020.

Since we are assuming an exponential growth, the population in year t is given by a function

\bf P(t)= Ce^{kt}

where C and k are constants to be determined.

We can take 1980 as year 0. This way calculations are lighter. 1990 is year 10 and 2020 is year 20.

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So far we have

\bf P(t)= 10.3e^{kt}

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\bf 10.3e^{k*10}=12.5\rightarrow e^{10k}=\frac{12.5}{10.3}=1.21359\rightarrow \\10k=log(1.21359)\rightarrow k=0.01936

And the function that models the population growth is

\bf P(t)= 10.3e^{0.01936t}

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We must reduce 118,781.1 down to 29,362.5

Hence the new CO emission factor would be

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