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Shalnov [3]
3 years ago
11

What is larger  3/8  or  5/16

Mathematics
2 answers:
UkoKoshka [18]3 years ago
7 0
\frac{3}{8} ... \frac{5}{16}

First, find the least common denominator between the two.
Since 8 is a factor of 16, the LCD is 16.

\frac{3*2}{8*2}

\frac{3}{8}=  \frac{6}{16}

Now, you can compare the numerators.

6>5

Since 6 is greater than 5, you know that \frac{6}{16} > \frac{5}{16}.

Therefore, we now know that \frac{3}{8} is larger.
11Alexandr11 [23.1K]3 years ago
6 0
\frac{3}{8}=\frac{3\codt2}{8\cdot2}=\frac{6}{16} > \frac{5}{16}\\\\Answer:\frac{3}{8}\ is\ larger\ than\ \frac{5}{16}.
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How do I solve this finding the first four of the sequence?
Gemiola [76]

Answer:

300,350,400,450

Step-by-step explanation:

the formula for any n term is:

tn=a1+(n-1)d

t1= 300+(1-1)d=300

t2= 300+(2-1)50= 350

t3= 300+(3-1)50= 400

t4= 300+(4-1)50 = 450

and so on...

5 0
3 years ago
Write the equation of circle b with center B(-2,3) that passes through (1,2)
professor190 [17]

Answer:

(x+2)^2 + (y-3)^2 = 10

Step-by-step explanation:

The standard equation for circle is

(x-a)^2 + (y-b)^2 = r^2

where point (a,b) is coordinate of center of circle and r is the radius.

______________________________________________________

Given

center of circle =((-2,3)

let r be the radius of circle

Plugging in this value of center in standard equation for circle given above we have

(x-a)^2 + (y-b)^2 = r^2    \ substitute (a,b) \ with (-2,3) \\=>(x-(-2))^2 + (y-3)^2 = r^2  \\=>(x+2)^2 + (y-3)^2 = r^2    (1)

Given that point (1,2 ) passes through circle. Hence this point will satisfy the above equation of circle.

Plugging in the point (1,2 )  in equation 1 we have

\\=>(x+2)^2 + (y-3)^2 = r^2    \\=> (1+2)^2 + (2-3)^2 = r^2\\=> 3^2 + (-1)^2 = r^2\\=> 9 + 1 = r^2\\=> 10 = r^2\\=>  r^2  = 10\\

now we have value of r^2 = 10, substituting this in equation 1 we have

Thus complete equation of circle is =>(x+2)^2 + (y-3)^2 = r^2\\=>(x+2)^2 + (y-3)^2 = 10

7 0
3 years ago
What is the product 4n/4n-4 n-1/n+1
olga_2 [115]
4n/4n-4 × n-1/n+1
= 4n(n-1)/(4n-4)(n+1)
= (4n^2 - 4n)/(4n^2 + 4n - 4n-4)
= (4n^2 - 4n)/(4n^2 - 4)
= 4(n^2 - n)/4(n^2 - 1)
=(n^2 - n)/(n^2 - 1)
5 0
4 years ago
Cameron's uncle is 3 times old as he is. 4 years ago, he was 4 times older. How old is Cameron?
erma4kov [3.2K]

Let Cameron be x years old now.

-

<u>Now:</u>

Cameron = x

Uncle =3x

-

<u>4 years ago:</u>

Cameron = x - 4

Uncle = 3x - 4

-

<u>4 years ago, Uncle is 4 times older:</u>

3x - 4 = 4(x - 4)

-

<u>Find x:</u>

3x - 4 = 4(x - 4)

3x - 4 = 4x - 16

4x - 3x = 16 - 4

x = 12

-

<u>Find the age:</u>

Cameron = x = 12

-

Answer: Cameron is 12 years old now.

3 0
3 years ago
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$$ \sqrt{6\frac{1}{4}} $$
ratelena [41]
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6 0
3 years ago
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