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Naddik [55]
2 years ago
14

The question is in the attached picture​

Mathematics
1 answer:
GarryVolchara [31]2 years ago
7 0

Answer: \frac{1}{3} \sin x^{3}+C

Step-by-step explanation:

Let u=x^3. Then, 3x^2 dx = du \longrightarrow x^2 dx =\frac{1}{3}du

So, we can rewrite the original integral as

\frac{1}{3} \int \cos u \text{ } du=\frac{1}{3} \sin u+C=\frac{1}{3} \sin x^{3}+C

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