1 year ago

8. In AABC, LA is a right angle and mzB = 45°. Find BC.

Mathematics

1 answer:

Margaret [11]1 year ago

7 0

Answer:

BC = 11 $\sqrt{2}$

Step-by-step explanation:

using the sine ratio in the right triangle and the exact value

sin45° = $\frac{1}{\sqrt{2} }$ , then

sin 45° = $\frac{opposite}{hypotenuse}$ = $\frac{AC}{BC}$ = $\frac{11}{BC}$ = $\frac{1}{\sqrt{2} }$ ( cross- multiply )

BC = 11 $\sqrt{2}$

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