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Lana71 [14]
2 years ago
15

8. In AABC, LA is a right angle and mzB = 45°. Find BC.

Mathematics
1 answer:
Margaret [11]2 years ago
7 0

Answer:

BC = 11\sqrt{2}

Step-by-step explanation:

using the sine ratio in the right triangle and the exact value

sin45° = \frac{1}{\sqrt{2} } , then

sin 45° = \frac{opposite}{hypotenuse} = \frac{AC}{BC} = \frac{11}{BC} = \frac{1}{\sqrt{2} } ( cross- multiply )

BC = 11\sqrt{2}

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