The perimeter of a rectangle is 200 yards. what are the dimensions of the rectangle if the length is 80 yards more than the? wid
th?
1 answer:
P = 2(L + W)
P = 200
L = W + 80
200 = 2(W + 80 + W)
200 = 2(2W + 80)
200 = 4W + 160
200 - 160 = 4W
40 = 4W
40/4 = W
10 = W.........the width is 10 yds
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