X is 90 degrees. If AB is the diameter, then it passes through the centre. X is 90 degrees because the angle in a semicircle is always a right angle.
Answer:
1) y=(-1/4)x+(11/4)
2) y=(4)x-33
3) y=(2/3)x-11/3
4) y=(5)x-2
5) y=(3)x-7
6) y=(-1/4)x+(6)
Step-by-step explanation:
1) y=mx+b 3=(-1/4)(-1)+b b= 11/4
2) y=mx+b -5=(4)(7)+b b= -33
3) y=mx+b -5=(2/3)(-2)+b b= -11/3
4) y=mx+b 3=(5)(1)+b b= -2
5) y=mx+b -1=(-3)(-2)+b b= -7
6) y=mx+b 7=(1/4)(4)+b b= 6
Answer:
Therefore, HL theorem we will prove for Triangles Congruent.
Step-by-step explanation:
Given:
Label the Figure first, Such that
Angle ADB = 90 degrees,
angle ADC = 90 degrees, and
AB ≅ AC
To Prove:
ΔABD ≅ ΔACD by Hypotenuse Leg theorem
Proof:
In Δ ABD and Δ ACD
AB ≅ AC ……….{Hypotenuse are equal Given}
∠ADB ≅ ∠ADC ……….{Each angle measure is 90° given}
AD ≅ AD ……….{Reflexive Property or Common side}
Δ ABD ≅ Δ ACD ….{By Hypotenuse Leg test} ......Proved
Therefore, HL theorem we will prove for Triangles Congruent.
Answer:
y=3
Step-by-step explanation:
F(x)=f(-2) so go to -2 on the x axis and then find the y