All categories

1 year ago

Given a sphere with a radius of 2 cm, find its volume to the nearest whole

Mathematics

1 answer:

Anton [14]1 year ago

7 0

Answer: 34

Step-by-step explanation:

$V=\frac{4}{3}(\pi)(2^{3}) \approx \boxed{34}$

You might be interested in

A certain recipe requires 415 cups of flour and 237 cups of sugar. a) If 49 of the recipe is to be made, how much sugar is neede

Bas_tet [7]

49*237

11613

That's a lot of sugar, diabetes here we come :)

7 0

2 years ago

Can someone please help me with this problem asap? Thanks!! :))

ivolga24 [154]

Answer: $\$4.34$

Step-by-step explanation:

We have the following information:

Fredburguer $F$ , milkshake $M$ and an order of fries $f$ costs $\$3.72$ :

$F+M+f=\$3.72$ (1)

One Fredburguer is equal to a milkshake plus orders of fries:

$F=M+2f$ (2)

Three milshakes is equal to a Fredburguer plus an order of fries:

$3M=F+f$ (3)

And we are asked: If we have a Fredburguer, a milkshake and two orders of fries, how much do we have to pay?

$F+M+2f=x$ (4)

Well with the first three equations we have a system of equations to solve. Let's begin by isolating $F$ from (3):

$F=3M-f$ (5)

Making (2)=(5):

$M+2f=3M-f$ (6)

Isolating $f$ :

$f=\frac{2}{3}M$ (7)

Substituting (7) in (2):

$F=M+2(\frac{2}{3}M)$ (8)

Isolating $F$ :

$F=\frac{7}{3}M$ (9)

Substituting (7) and (9) in (1):

$\frac{7}{3}M+M+\frac{2}{3}M=\$3.72$ (10)

Isolating $M$ :

$M=\$0.93$ (11) This is the cost of a Milkshake

Substituting (11) in (7):

$f=\frac{2}{3}\$0.93$ (12)

$f=\$0.62$ (13) This is the cost of an order of frieds

Substituting (11) in (9):

$F=\frac{7}{3}\$0.93$ (14)

$F=\$2.17$ (15) This is the cost of a Fredburguer

Substituting (11), (13) and (15) in (4):

$\$2.17+\$0.93+2(\$0.62)=x$ (16)

Finally:

$x=\$4.34$ This is the cost of a Fredburguer, a milkshake and two orders of fries

8 0

2 years ago

PLZ HELP

Juliette [100K]

Answer:

N = 1/2x + 6

Step-by-step explanation:

We know that Jane has 6 more shoes than 1/2 of what Mercedes has. We can use this information to make an equation.

N (or number of shoes Jane has) is equal to 1/2x (or the number of shoes Mercedes has) plus 6.

When written out we get our answer of:

N + 1/2x + 6

3 0

2 years ago

Find tge gcf of 14ab, 7a

strojnjashka [21]

Dividing both numbers by 7a gives 2b, and 1.
Therefore the greatest common factor (GCF) is 7a.

3 0

2 years ago

Please answer this question

Tems11 [23]

$\bold{\huge{\underline{ Solution }}}$

<h3>Given :- </h3>

• $\sf{ Polynomial :- ax^{2} + bx + c }$

• The zeroes of the given polynomial are α and β .

<h3>Let's Begin :- </h3>

Here, we have polynomial

$\sf{ = ax^{2} + bx + c }$

We know that, 

Sum of the zeroes of the quadratic polynomial

$\sf{ {\alpha} + {\beta} = {\dfrac{-b}{a}}}$

And 

Product of zeroes

$\sf{ {\alpha}{\beta} = {\dfrac{c}{a}}}$

Now, we have to find the polynomials having zeroes :-

$\sf{ {\dfrac{{\alpha} + 1 }{{\beta}}} ,{\dfrac{{\beta} + 1 }{{\alpha}}}}$

Therefore ,

Sum of the zeroes

$\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} )+( {\beta}+{\dfrac{1 }{{\alpha}}})}$

$\sf{ ( {\alpha} + {\beta}) + ( {\dfrac{1}{{\beta}}} +{\dfrac{1 }{{\alpha}}})}$

$\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{{\alpha}+{\beta}}{{\alpha}{\beta}}}}$

$\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{-b/a}{c/a}}}$

$\sf{ {\dfrac{ -b}{a}} + {\dfrac{-b}{c}}}$

$\bold{{\dfrac{ -bc - ab}{ac}}}$

Thus, The sum of the zeroes of the quadratic polynomial are -bc - ab/ac

Product of zeroes

$\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} ){\times}( {\beta}+{\dfrac{1 }{{\alpha}}})}$

$\sf{ {\alpha}{\beta} + 1 + 1 + {\dfrac{1}{{\alpha}{\beta}}}}$

$\sf{ {\alpha}{\beta} + 2 + {\dfrac{1}{{\alpha}{\beta}}}}$

$\bold{ {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}$

Hence, The product of the zeroes are c/a + a/c + 2 .

We know that, 

For any quadratic equation

$\sf{ x^{2} + ( sum\: of \:zeroes )x + product\:of\: zeroes }$

$\bold{ x^{2} + ( {\dfrac{ -bc - ab}{ac}} )x + {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}$

Hence, The polynomial is x² + (-bc-ab/c)x + c/a + a/c + 2 .

<h3>Some basic information :-</h3>

• Polynomial is algebraic expression which contains coffiecients are variables.

• There are different types of polynomial like linear polynomial , quadratic polynomial , cubic polynomial etc.

• Quadratic polynomials are those polynomials which having highest power of degree as 2 .

• The general form of quadratic equation is ax² + bx + c.

• The quadratic equation can be solved by factorization method, quadratic formula or completing square method.

6 0

1 year ago