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irga5000 [103]
3 years ago
10

Three to the fourth power. Write the numerical answer only.

Mathematics
1 answer:
irakobra [83]3 years ago
8 0
30000 is the answer I think
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The graph of f "(x) is continuous and decreasing with an x-intercept at x = 0. Which of the following statements is true?
kari74 [83]

Answer:

The graph of f has an inflection point at x = 0.

Step-by-step explanation:

An inflection point occurs when the second derivative changes signs.  Since f"(x) is decreasing and has an x-intercept at 0, it changes signs from + to -, so there is an inflection point at x = 0.

7 0
4 years ago
What is the solution to the equation x + 11 = 57? (Input a whole number only.) Numerical Answers Expected! Answer for Blank 1:
tigry1 [53]
Rearrange to get x on its own on one side of the equation:
x = 57 - 11
x = 46
7 0
3 years ago
Read 2 more answers
help me please i got the answer which is 2 but how do i do the sqrt 3 part in the bottom in gold letters
Allisa [31]

|MN| =\sqrt{(x_{M}-x_{N})^{2}+(y_{M} - y_{N})^{2}} =\sqrt{(-6-(-1))^{2}+(-1-(-7))^{2}} = \\ \\ =\sqrt{25 +36} =\sqrt{61}  \\ \\Answer \ is \  \sqrt{61} .

4 0
3 years ago
(**15 POINTS**)
bonufazy [111]

Answer:

0.6x = 87

Step-by-step explanation:

Hi, to answer this question we have to write en equation:

We have to multiply the variable x by the percentage given (60%) in decimal form (divided by 100). That expression must be equal to 87.

Mathematically speaking:

x (60/100) = 87

0.6x = 87

Feel free to ask for more if needed or if you did not understand something.

8 0
3 years ago
Minimum Average Cost
Dahasolnce [82]

Answer:

a)\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}

b)\bar{C}(x)=5.81

Step-by-step explanation:

Given that

C = 100 + 25 x - 120 ln x   ,x ≥ 1.

The average cost function given as

\bar{C}(x)=\dfrac{C(x)}{x}

\bar{C}(x)=\dfrac{100 + 25 x - 120 \ln x}{x}

\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx{x}

Therefore

\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}

To find average minimum cost

\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}

\dfrac{d\bar{C}(x)}{dx} = -\dfrac{100}{x^2} +0-120\times \dfrac{1-lnx}{x^2}

0 = -\dfrac{100}{x^2} +0- 120\times \dfrac{1-lnx}{x^2}

100 + 120 (1-lnx) = 0

lnx=\dfrac{220}{120}

ln x =1.833

x=e^{1.833}

x=6.25

\bar{C}(x)=\dfrac{100}{6.25}+25-120\dfrac{ln6.25}{6.25}

\bar{C}(x)=5.81

6 0
4 years ago
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