1 year ago

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Mathematics

1 answer:

umka21 [38]1 year ago

6 0

Answer:

Therefore, an integer that's divisible by both 6 and 9 has at least one 2 and two 3s in its prime factorization. That means it is divisible by 2 and 3: 2 x 3 6, 3 x 3 9, and 2 x 3 x 3 = 18. It's not necessarily divisible by 12 or 36, each of which includes two 2s in its prime factorization

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