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kotykmax [81]
3 years ago
15

A club is making posters to raise money. The printer charges a base fee of $270 and $2 per poster for supplies. A person sells e

ach poster for $ 5. How many posters must he sell to make a profit of $ 300?
Mathematics
1 answer:
sesenic [268]3 years ago
6 0

<u>Answer:</u>

He must sell 190 posters make a profit of $300.

<u>Explanation: </u>

Given:

Base fee= $270  

Fee for supplies= $2

Cost of poster=$5

To find:

The number of posters to be sold to get a profit of $300=?

Solution:

Let the number of posters sold be n.

Now, we know that,

profit = selling price – cost price

$ 300 = $ 5 for each poster – ( $ 270 base fee + $ 2 for each poster)

300 = 5 x n – (270 + 2 x n)  

300 = 5n – 270 – 2n  

5n – 2n = 300 + 270  

3n = 570  

n=\frac{570}{3}

n = 190

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560

Step-by-step explanation:

1=160

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JUST ADD 160 EACH TIME

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From a standard deck of 52 cards, what is the probability of picking a King at random from the deck?
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Answer:

1/13

Step-by-step explanation:

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There are 24 muffins in a bakery. If 3/8 of the muffins are blueberry, how many muffins are blueberry?
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An Epson inkjet printer ad advertises that the black ink cartridge will provide enough ink for an average of 245 pages. Assume t
Neko [114]

Answer:

35.2% probability that the sample mean will be 246 pages or more

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 245 \sigma = 15, n = 33, s = \frac{15}{\sqrt{33}} = 2.61

What the probability that the sample mean will be 246 pages or more?

This is 1 subtracted by the pvalue of Z when X = 246. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{246 - 245}{2.61}

Z = 0.38

Z = 0.38 has a pvalue of 0.6480.

1 - 0.6480 = 0.3520

35.2% probability that the sample mean will be 246 pages or more

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How do i turn 3/8 into a percent
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Multiply by 100
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