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musickatia [10]

1 year ago

7

Use the figure below to find the answer.

1 answer:

Serhud [2]1 year ago

4 0

Answer: $\frac{7\sqrt{2}}{2}$

Step-by-step explanation:

$\sin 45^{\circ}=\frac{7}{y}\\\\\frac{1}{\sqrt{2}}=\frac{7}{y}\\\\y=\frac{7}{\sqrt{2}}=\boxed{\frac{7\sqrt{2}}{2}}$

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Solve for P must convert 3 months inyo years has picture

Studentka2010 [4]

A year has 12 months so 1 month = 1/12 year. t = 3 months = 3/12 year = 1/4 year

3 0

3 years ago

Write the values that make the denominators zero. then solve the equation?

Olin [163]

Answer:

denominators are zero for x=1

there is no solution

Step-by-step explanation:

We suspect your equation is supposed to be ...

10/(5x -5) +1/5 = 2/(x -1) . . . . . parentheses are required on denominators

The denominators will be zero for x=1.

This version of the equation has no solution. It simplifies to ...

2/(x-1) + 1/5 = 2/(x -1)

1/5 = 0 . . . . . subtract 2/(x-1) from both sides

There is no value of x that will make this equation true.

_____

<em>Alternative interpretation</em>

The way your equation is written, it must be interpreted according to the order of operations to be ...

(10/5)x -5 +1/5 = (2/x) -1 . . . . x=0 makes the denominator zero

2x -3.8 = 2/x

2x^2 -3.8x = 2 . . . . multiply by x

2(x^2 -1.9x +.95^2) = 2 +2(0.95^2)

(x -0.95)^2 = 1.9025

x = 0.95 ± √1.9025 ≈ {-0.4293, 2.3293}

4 0

3 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

What is 65/8 as a mixed number

Stolb23 [73]

$List\ of\ the\ multiples\ of\ 8:0;\ 8;\ 126;\ 24;\ 32;\ 40;\ 48;\ 56;\ \boxed{64}\\\\\frac{65}{8}=\frac{64+1}{8}=\frac{64}{8}+\frac{1}{8}=\boxed{8\frac{1}{8}}$

6 0

2 years ago

Read 2 more answers

Hurrryy!!!<br> im on a timerrr

docker41 [41]

Answer:

3rd one

Step-by-step explanation:

12

5 0

2 years ago