Answer:
A = 26
Step-by-step explanation:
sum of students = classA + classB + classC
let's say classA = A, classB = B, and classC = C
A + B + C = 66
class A has five more students than class B, so A = 5 more than B so A = 5+B
class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2
A + B + C = 66
A = 5+B
C = B-2
substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)
(5+B) + B + (B-2) = 66
3B + 3 = 66
subtract 3 from both sides to isolate the variable and its coefficient
3B = 63
divide both sides by 3 to solve for B
B = 21
A = 5 + B = 5 + 21 = 26
Volume of a sphere = (4/3)πr³ π ≈ 3.14, r = 9
Volume, V = (4/3)πr³
V ≈ (4/3)*3.14*9³
V ≈ (4/3)*3.14*9*9*9 Use calculator
V ≈ 3052.08
Option A.
Hope this helps.
Answer:
1. Complex number.
2. Imaginary part of a complex number.
3. Real part of a complex number.
4. i
5. Multiplicative inverse.
6. Imaginary number.
7. Complex conjugate.
Step-by-step explanation:
1. <u><em>Complex number:</em></u> is the sum of a real number and an imaginary number: a + bi, where a is a real number and b is the imaginary part.
2. <u><em>Imaginary part of a complex number</em></u>: the part of a complex that is multiplied by i; so, the imaginary part of the complex number a + bi is b; the imaginary part of a complex number is a real number.
3. <em><u>Real part of a complex number</u></em>: the part of a complex that is not multiplied by i. So, the real part of the complex number a + bi is a; the real part of a complex number is a real number.
4. <u><em>i:</em></u> a number defined with the property that 12 = -1.
5. <em><u>Multiplicative inverse</u></em>: the inverse of a complex number a + bi is a complex number c + di such that the product of these two numbers equals 1.
6. <em><u>Imaginary number</u></em>: any nonzero multiple of i; this is the same as the square root of any negative real number.
7. <em><u>Complex conjugate</u></em>: the conjugate of a complex number has the opposite imaginary part. So, the conjugate of a + bi is a - bi. Likewise, the conjugate of a - bi is a + bi. So, complex conjugates always occur in pairs.
Select 4 from 9, and 3 from 8. Multiply together.
C(9,4)*C(8,3)
=9!/(4!5!) * 8!/(3!5!)
=7056
Y = 1/3x - 2.
If you sub in 0, you’ll get (0, -2) which is the y intercept.