Question

Pls help me solve for x in this equation! + brainest

Answer 1

Answer:

x = -3

Explanation:

$\rightarrow \sf \sqrt[3]{\sf 3x + 1} = -2$

$\rightarrow \sf \sf 3x + 1 = (-2)^3$

$\rightarrow \sf \sf 3x + 1 = -8$

$\rightarrow \sf \sf 3x = -8-1$

$\rightarrow \sf \sf 3x = -9$

$\rightarrow \sf \sf x = -3$

Answer 2

Answer:

$\sqrt[3]{3x+1} =-2\\(\sqrt[3]{3x+1})^{3} =(-2)^{3} \\3x+1=-8\\3x=-9\\x=-3$

Hope it helps!