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zloy xaker [14]
2 years ago
5

33. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.

Mathematics
1 answer:
german2 years ago
7 0

Answer:

The linear equation for the line which passes through the points given as (1,5) and (4,11), is written in the point-slope form as y=2x+3.

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (1,5) and (4,11).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 2

Determine the slope of the line.

The points through which the line passes are given as (1,5) and (4,11). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute 11&5 for $y_{2}$ and $y_{1}$ respectively, and $4 \& 1$ for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows,

$$\begin{aligned}m &=\frac{11-5}{4-1} \\m &=\frac{6}{3} \\m &=2\end{aligned}$$

Step 2 of 2

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$$y-y_{1}=m\left(x-x_{1}\right)$$

Substitute 2 for $m, 1$ for $x_{1}$, and 5 for $y_{1}$ in the above equation and simplify using the distributive property as follows,

$$\begin{aligned}&y-5=2(x-1) \\&y-5=2 x-2 \\&y=2 x-2+5 \\&y=2 x+3\end{aligned}$$

This is the required linear equation.

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In Game 1, Emerson struck out 30 times in 90 times at bat. In Game 2, he struck out 40 times in 120 times at bat. In Game 3, Eme
VikaD [51]

Answer:

<u>Total number of strikeouts:</u>

  • 30 + 40 + 42 = 112

<u>Total number of at bats:</u>

  • 90 + 120 + 140 = 350

<u>Hits = times - strikeouts:</u>

  • 350 - 112 = 238

<u>Percentage:</u>

  • 238/352*100% = 67.61%

7 0
3 years ago
The regular pentagon shown has an apothem with a length of 2 centimeters. To the nearest tenth, what is the area of the regular
Rom4ik [11]

Answer:

11.8cm²

Step-by-step explanation:

The area of the regular pentagon is expressed as;

A = pa/2

p is the perimeter of the pentagon

a is the apothem

Since p = 5s

s is the side length, hence;

A = 5sa/2

Get the side length s;

central angle = 360/5

central angle = 72degrees

angle in the right angle triangle =72/2 = 36degrees

Using SOH CAH TOA

sin 36 = x/2

x = 2sin36

x = 1.1755

s = 2x

s = 2.35cm

Get the area

A = 5(2.35)(2)/2

A = 5(2.35)

A = 11.8cm²

Hence the area of the regular pentagon is 11.8cm²

8 0
3 years ago
Read 2 more answers
the length of the sides forming a right angle of a right-angled triangle is 5 x cm and 3 X - 1 cm. area of the triangle is 60 CM
Paladinen [302]

hypotenuse (h) = 17 cm

using area of a triangle formula to solve for x

A = \frac{1}{2} bh ( b is the base and h the height )

\frac{1}{2} × 5x(3x - 1 ) =60 ( multiply through by 2 )

5x(3x - 1)=120

15x² - 5x - 120 = 0 ← in standard form ( divide all terms by 5 )

3x² - x - 24 = 0

consider the factors of the product 3 × - 24 = - 72 which sum to - 1

The factors are - 9 and + 8 ( split the middle term using these factors )

3x² - 9x + 8x - 24 = 0 ( factor by grouping )

3x(x - 3) + 8(x - 3) = 0 ( take out common factor (x - 3) )

(x - 3 )(3x + 8) = 0 ( equate each factor to zero and solve for x )

x - 3 = 0 ⇒ x = 3

3x + 8 = 0 ⇒ x = - \frac{8}{3}

x > 0 ⇒ x = 3

the sides are 5x = 15 and 3x - 1 = 8

h = √(15² + 8² ) = √(225 + 64 ) = 17 ← ( hypotenuse )








8 0
3 years ago
Please help asap thanks
QveST [7]

Answer:

All functions are relations

Step-by-step explanation:

4 0
3 years ago
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