The regular pentagon shown has an apothem with a length of 2 centimeters. To the nearest tenth, what is the area of the regular
pentagon in square cintimeters
2 answers:
Answer:
11.8cm²
Step-by-step explanation:
The area of the regular pentagon is expressed as;
A = pa/2
p is the perimeter of the pentagon
a is the apothem
Since p = 5s
s is the side length, hence;
A = 5sa/2
Get the side length s;
central angle = 360/5
central angle = 72degrees
angle in the right angle triangle =72/2 = 36degrees
Using SOH CAH TOA
sin 36 = x/2
x = 2sin36
x = 1.1755
s = 2x
s = 2.35cm
Get the area
A = 5(2.35)(2)/2
A = 5(2.35)
A = 11.8cm²
Hence the area of the regular pentagon is 11.8cm²
Answer:
11.8cM
Step-by-step explanation:
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Answer:
180-79-37=101-37=64
y=64 degrees
Answer:
X=(5/4)^-10
Step-by-step explanation:
(5/4)^6÷x=(25/16)^8
(5/4)^6÷x=(5/4)^16
1/X==(5/4)^16÷(5/4)^6
X=(5/4)^6÷(5/4)^16
X=(5/4)^-10
So the value of X is (5/4)^-10
Thanks for the free points! Have a fantastic day!
The answer is c I hope that helps you
Answer:
48
Step-by-step explanation:
25% of x = 0.25
12/0.25 = 48