Answer:
Step-by-step explanation:
(-2)^-3=
=
- = -0.125
<span>Simplify <span>18*<span>x/3</span></span> to <span>6x</span>
</span><span><span>6<span>x^8</span>+21<span>x^2</span>−6x</span></span>
A graph that cuts for y = 3
Let's define the vectors:
U = (4.4)
V = (3.1)
The projection of U into V is proportional to V
The way to calculate it is the following:
Proy v U = [(U.V) / | V | ^ 2] V
Where U.V is the point product of the vectors, | V | ^ 2 is the magnitude of the vector V squared and all that operation by V which is the vector.
We have then:
U.V Product:
U.V = (4,4) * (3,1)
U.V = 4 * 3 + 4 * 1
U.V = 12 + 4
U.V = 16
Magnitude of vector V:
lVl = root ((3) ^ 2 + (1) ^ 2)
lVl = root (9 + 1)
lVl = root (10)
Substituting in the formula we have:
Proy v U = [(16) / (root (10)) ^ 2] (3, 1)
Proy v U = [16/10] (3, 1)
Proy v U = [1.6] (3, 1)
Proy v U = [1.6] (3, 1)
Proy v U = (4.8, 1.6)
Answer:
the projection of (4,4) onto (3,1) is:
Proy v U = (4.8, 1.6)
Answer:
(D)On a coordinate plane, a parabola opens up with x-intercepts at (negative 2, 0) and (2, 0), and a y-intercept at the vertex (0, negative 4).
Step-by-step explanation:
For a parabola to have a minimum vertex, it must open upward. (a>0).
In the given options, the parabola which opens upward is option D.
On a coordinate plane, a parabola opens up with x-intercepts at (negative 2, 0) and (2, 0), and a y-intercept at the vertex (0, negative 4).
Therefore, it has a minimum vertex with coordinates (0,-4).