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Mariulka [41]
3 years ago
8

Help me on this question

Mathematics
1 answer:
olganol [36]3 years ago
5 0

Answer:

  see below

Step-by-step explanation:

All of the given data sets have x-values that are sequential with a difference of 1. That makes it easy to determine the sort of sequence the y-values make.

  <u>first choice</u>: the y-values have a common difference of -2. This will be matched by a linear model.

 <u>second choice</u>: the y-values have a common difference of +2. Again, this will be matched by a linear model.

  <u>third choice</u>: the y-values have a common ratio of -2. This will be matched by an exponential model.

  <u>fourth choice</u>: the y-value differences are 3, 5, 7, increasing by a constant amount (2). This is characteristic of a sequence that has a quadratic model.

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Find one value of x that is a solution to the equation:<br>(x^2– 8)^2 + x^2 – 8 = 20<br>x=​
Kipish [7]

Answer:

x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

Step-by-step explanation:

Solve for x:

-8 + x^2 + (x^2 - 8)^2 = 20

Expand out terms of the left hand side:

x^4 - 15 x^2 + 56 = 20

Subtract 20 from both sides:

x^4 - 15 x^2 + 36 = 0

Substitute y = x^2:

y^2 - 15 y + 36 = 0

The left hand side factors into a product with two terms:

(y - 12) (y - 3) = 0

Split into two equations:

y - 12 = 0 or y - 3 = 0

Add 12 to both sides:

y = 12 or y - 3 = 0

Substitute back for y = x^2:

x^2 = 12 or y - 3 = 0

Take the square root of both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y - 3 = 0

Add 3 to both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y = 3

Substitute back for y = x^2:

x = 2 sqrt(3) or x = -2 sqrt(3) or x^2 = 3

Take the square root of both sides:

Answer: x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

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3 years ago
59:19
Vesna [10]

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Step-by-step explanation: .

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Point q is the image of Q(5, -3) after a translation down 2 units and right 4 units. What are the coordinates of Q?
Jet001 [13]

Answer:

<em>(9,-5)</em>

Step-by-step explanation:

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<em>(9,-5)</em>

<u>Hope this helps :-)</u>

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We have no idea how much is one faithful of a barrel.

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