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![Let's \ first \ rearrange \ the \ equation! \\ \\ ( 2/10-(4/a-3)=0 ) \\ \\ we \ first \ simply \ simplify \ first \ \boxed{ \frac{4}{a} } \\ \\ \left[\begin{array}{ccc}\ \left[\begin{array}{ccc}\boxed{ \frac{2}{10}-( \frac{4}{a})-3)=0} \end{array}\right] \end{array}\right] \\ \\ We \ then \ subtract \ its \ whole \ numbers. \\ \\ \boxed{3= \frac{3}{1} = \frac{3*a}{a} } \\ \\](https://tex.z-dn.net/?f=Let%27s%20%5C%20first%20%5C%20rearrange%20%5C%20the%20%5C%20equation%21%20%5C%5C%20%5C%5C%20%28%20%20%20%20%202%2F10-%284%2Fa-3%29%3D0%20%29%20%5C%5C%20%5C%5C%20we%20%5C%20first%20%5C%20simply%20%5C%20simplify%20%5C%20first%20%5C%20%5Cboxed%7B%20%5Cfrac%7B4%7D%7Ba%7D%20%7D%20%5C%5C%20%5C%5C%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5C%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%20%5Cfrac%7B2%7D%7B10%7D-%28%20%5Cfrac%7B4%7D%7Ba%7D%29-3%29%3D0%7D%20%5Cend%7Barray%7D%5Cright%5D%20%5Cend%7Barray%7D%5Cright%5D%20%20%5C%5C%20%5C%5C%20We%20%5C%20then%20%5C%20subtract%20%5C%20its%20%5C%20whole%20%5C%20numbers.%20%5C%5C%20%5C%5C%20%5Cboxed%7B3%3D%20%5Cfrac%7B3%7D%7B1%7D%20%3D%20%5Cfrac%7B3%2Aa%7D%7Ba%7D%20%7D%20%5C%5C%20%5C%5C%20)
![\Longrightarrow \left[\begin{array}{ccc}2/10-(4-3a)/a=\boxed{0}\end{array}\right] \\ \\ we \ then \ simplify \ \boxed{1/5 \\ \\ 1/5-(4-3a)/a=0} \\ \\ \\ \boxed{\boxed{ \frac{a-((4-3a)*5}{5a} = \frac{16a-20}{5a} }} \\ \\ we \ then \ pull \ out \ some \ like \ terms . \\ \\ 16a - 20 = 4 * (4a - 5) \\ \\ solve \ 4 = 0 \ ; solve \ 4a-5 = 0 . \\ \\ \Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow](https://tex.z-dn.net/?f=%5CLongrightarrow%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%2F10-%284-3a%29%2Fa%3D%5Cboxed%7B0%7D%5Cend%7Barray%7D%5Cright%5D%20%20%5C%5C%20%5C%5C%20we%20%5C%20then%20%5C%20simplify%20%5C%20%5Cboxed%7B1%2F5%20%5C%5C%20%5C%5C%201%2F5-%284-3a%29%2Fa%3D0%7D%20%5C%5C%20%5C%5C%20%5C%5C%20%5Cboxed%7B%5Cboxed%7B%20%5Cfrac%7Ba-%28%284-3a%29%2A5%7D%7B5a%7D%20%3D%20%5Cfrac%7B16a-20%7D%7B5a%7D%20%7D%7D%20%5C%5C%20%5C%5C%20%20we%20%5C%20then%20%5C%20pull%20%5C%20out%20%5C%20some%20%5C%20like%20%5C%20terms%20.%20%5C%5C%20%5C%5C%20%20%2016a%20-%2020%20%20%3D%20%20%204%20%2A%20%284a%20-%205%29%20%5C%5C%20%5C%5C%20%20solve%20%5C%20%204%20%20%20%3D%20%200%20%5C%20%3B%20solve%20%5C%204a-5%20%3D%200%20.%20%5C%5C%20%5C%5C%20%0A%0A%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow%5CDownarrow)
![\boxed{TAKE \ NOTICE} \\ \\ \\ \boxed{\boxed{ Add \ 5 \ to \ both \ sides \ of \ the \ equation : \ 4a = 5 }} \\ \\ \\ \left[\begin{array}{ccc} \left[\begin{array}{ccc}Divide \ both \ sides \ of \ the \ equation \ by \4: \\ a = 5/4 = 1.250 \end{array}\right] \end{array}\right] \\ \\ \\ \boxed{\boxed{Your \ correct \ answers}}... \\ \\ \\ \boxed{ a = 5/4 = 1.250}](https://tex.z-dn.net/?f=%20%5Cboxed%7BTAKE%20%5C%20NOTICE%7D%20%5C%5C%20%5C%5C%20%5C%5C%20%5Cboxed%7B%5Cboxed%7B%20Add%20%5C%20%205%20%20%5C%20to%20%5C%20both%20%5C%20sides%20%5C%20of%20%20%5C%20the%20%5C%20equation%20%3A%20%5C%20%20%204a%20%3D%205%20%7D%7D%20%5C%5C%20%5C%5C%20%5C%5C%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7DDivide%20%20%5C%20both%20%5C%20sides%20%5C%20of%20%5C%20the%20%5C%20equation%20%5C%20by%20%20%5C4%3A%20%5C%5C%0A%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20a%20%3D%205%2F4%20%3D%201.250%20%5Cend%7Barray%7D%5Cright%5D%20%5Cend%7Barray%7D%5Cright%5D%20%20%5C%5C%20%5C%5C%20%5C%5C%20%5Cboxed%7B%5Cboxed%7BYour%20%5C%20correct%20%5C%20answers%7D%7D...%20%5C%5C%20%5C%5C%20%5C%5C%20%5Cboxed%7B%20%20a%20%3D%205%2F4%20%3D%201.250%7D)
I hope this helps you Cher!
I hope this helps you Cher!
Help me on this question
1 answer:
Answer:
see below
Step-by-step explanation:
All of the given data sets have x-values that are sequential with a difference of 1. That makes it easy to determine the sort of sequence the y-values make.
<u>first choice</u>: the y-values have a common difference of -2. This will be matched by a linear model.
<u>second choice</u>: the y-values have a common difference of +2. Again, this will be matched by a linear model.
<u>third choice</u>: the y-values have a common ratio of -2. This will be matched by an exponential model.
<u>fourth choice</u>: the y-value differences are 3, 5, 7, increasing by a constant amount (2). This is characteristic of a sequence that has a quadratic model.
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To solve this question, we use simple division:
So, there are 10 servings of 4/5 of a cup in 8 cups.
So, there are 10 servings of 4/5 of a cup in 8 cups.